Bourbaki

Exercise 4, § 1

Commutative Algebra, VIII, p. 81

a) Now prove that one can associate uniquely with every ordered set E an element of {−∞}∪N∪{+∞}\{ -\infty \} \cup \mathbf{N} \cup \{ +\infty \}, denoted dev(E) (deviation of E), in such a way that the following properties are satisfied: α) We have dev⁡(E)=−∞\operatorname{dev}(E) = -\infty if and only if the relation a≤ba \leq b in E implies a=ba = b. β) Let n be a positive integer. The deviation of E is ≤n\leq n if and only if, for every infinite decreasing sequence (ak)k∈N(a_k)_{k \in \mathbf{N}} of elements of E, one has dev⁡([ak,ak−1])≤n−1\operatorname{dev}([a_k, a_{k-1}]) \leq n - 1 for all sufficiently large k. b) In order that dev⁡(E)≤0\operatorname{dev}(E) \leq 0, it is necessary and sufficient that every strictly decreasing sequence of elements of E be stationary. We have dev⁡(N)=0\operatorname{dev}(\mathbf{N}) = 0, dev⁡(Z)=1\operatorname{dev}(\mathbf{Z}) = 1, dev⁡(Q)=+∞\operatorname{dev}(\mathbf{Q}) = +\infty. c) If E and F are ordered sets and f:E→Ff : E \to F is a strictly increasing mapping, we have dev⁡(E)≤dev⁡(F)\operatorname{dev}(E) \leq \operatorname{dev}(F). We have dev⁡(E×F)=sup⁡(dev⁡(E),dev⁡(F))\operatorname{dev}(E \times F) = \sup(\operatorname{dev}(E), \operatorname{dev}(F)). d) Let S(E) be the set of infinite increasing stationary sequences of elements of E, ordered by the product order. Then we have dev⁡(S(E))=dev⁡(E)+1\operatorname{dev}(S(E)) = \operatorname{dev}(E) + 1.

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.