Bourbaki

Exercise 4, § 2

Commutative Algebra, VIII

Let AA be an integrally closed local ring, mA\mathfrak{m}_A its maximal ideal and KK its field of fractions. For every element xx of KK, denote by A[x]A[x] the AA-subalgebra of KK generated by xx. Let xx be an element of K∗K^* such that x−1x^{-1} does not belong to AA. Let A[X]A[X] be the ring of polynomials in one indeterminate XX, with coefficients in AA, and let φ\varphi be the evaluation mapping P↦P(x)P \mapsto P(x) of A[X]A[X] onto A[x]A[x]. a) The kernel of φ\varphi is the ideal QQ generated by the polynomials of the form aX+baX + b, where a,b∈Aa, b \in A and ax+b=0ax + b = 0. (If P(X)=∑i=0naiXiP(X) = \sum_{i=0}^{n} a_i X^i is such that P(x)=0P(x) = 0, note that then −b0=a0x-b_0 = a_0 x is integral over AA and hence belongs to AA.) b) The ideal mAA[x]\mathfrak{m}_A A[x] of A[x]A[x] is prime, and it is maximal if and only if xx belongs to AA.

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.