Bourbaki

Exercise 8, § 2

Commutative Algebra, VIII, p. 85

Now prove that the polynomial ring A[X]A[X] is a faithfully flat AA-module, that for every maximal ideal mm of AA one has dim⁡(A[X]/mA[X])=1\dim(A[X]/mA[X]) = 1, and deduce from the preceding exercise the existence of ring homomorphisms ρ:A→B\rho : A \to B satisfying condition (PM) and such that dim⁡(B)>dim⁡(A)+inf⁡m∈Sdim⁡(B/mB)\dim(B) > \dim(A) + \inf_{m \in S} \dim(B/mB) (where SS is the set of maximal ideals of AA).

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.