Bourbaki

Exercise 2, § 3

Commutative Algebra, VIII, p. 87

Let AA be a noetherian integral ring. Suppose that AA is not a field and that the field of fractions of AA is a finitely generated AA-algebra. Then AA is semi-local and of dimension 1. (Show that there exists a nonzero and noninvertible element ff of AA such that A[f−1]A[f^{-1}] is a field, and reduce to proving that dim⁡(A/(f))=0\dim(A/(f)) = 0; if this were not so, A/(f)A/(f) would possess a prime ideal of height 1 whose inverse image p\mathfrak{p} in AA would be a prime ideal of height 2; but the local ring ApA_{\mathfrak{p}} of dimension 2 could have only a finite number of prime ideals, contrary to the prop. 6 of § 3, No. 3.)

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Machine translation of the English, by gpt-5-6. Not checked by a person.