Bourbaki

Exercise 2, § 4

Commutative Algebra, VIII, p. 88

Let f:Z→Zf : Z \to Z be a mapping. Prove that the following three properties are equivalent: a) There exist n0,n1n_0, n_1 in ZZ and PP in Q[T]Q[T] such that f(n)=0f(n) = 0 for n≤n1n \leq n_1 and f(n)=P(n)f(n) = P(n) for n≥n0n \geq n_0. b) There exists a finite support family (ai)i∈Z(a_i)_{i \in Z} of elements of ZZ such that f(n)=∑i∈Zai(n+ii)f(n) = \sum_{i \in Z} a_i \binom{n + i}{i} for all n∈Zn \in Z. c) There exist r∈Zr \in Z and Q∈Z[T,T−1]Q \in Z[T, T^{-1}] such that ∑n∈Zf(n)  Tn=(1−T)rQ(T)\sum_{n \in Z} f(n) \; T^n = (1 - T)^r Q(T). One then says that ff is polynomial at infinity. Generalize to the case of mappings from ZZ into an arbitrary ZZ-module.

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.