Bourbaki

Exercise 10, § 7

Commutative Algebra, VIII

Let A be a ring. (a) Let B be an integral A-algebra. Prove that for every element a of A and every ideal a of A, the element a is integral over a if and only if a is integral over the ideal a.B generated by a in B. (b) Assuming A noetherian and reduced, denote by p1,...,prp_1, ..., p_r the minimal prime ideals of A and consider the natural injection:

A→∏1⩽i⩽rA/pi. A \to \prod_{1 \leqslant i \leqslant r} A/p_i.
Prove that it makes ∏1⩽i⩽rA/pi\prod_{1 \leqslant i \leqslant r} A/p_i an integral A-algebra. (c) Deduce that, given a noetherian ring A, for an element a of A to be integral over an ideal a, it is necessary and sufficient that, for every minimal prime ideal p of A, the image of a in A/p is integral over the ideal (a+p)/p(a + p)/p. (d) Prove that if a‾=b‾\overline{a} = \overline{b}, the ideals a and b have the same associated minimal prime ideals.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.