Bourbaki

Exercise 14, § 7

Commutative Algebra, VIII

Let AA be a local ring, mm its maximal ideal, and qq an ideal of AA, distinct from AA, such that A/qA/q is of finite length. Suppose that AA contains a subfield kk such that A=k+mA = k + m. a) Now prove that there exist elements x1,...,xdx_1, ..., x_d of qq, where d=dim⁡(A)d = \dim(A), with xi∈qδix_i \in q^{\delta_i}, such that, for every sufficiently large integer v, one has qv=x1.qv−δ1+⋯+xd.qv−δdq^v = x_1.q^{v-\delta_1} + \cdots + x_d.q^{v-\delta_d}. b) If one supposes the field A/m infinite, one can find an ideal a generated by d elements of q; where d=dim⁡(A)d = \dim(A), such that a‾=q‾\overline{a} = \overline{q}. (One may use § 7, no 5.)

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