Bourbaki

Exercise 16, § 7

Commutative Algebra, VIII, p. 106

Let AA be a local noetherian ring and x=(x1,...,xd)x = (x_1, ..., x_d) an ideal generated by a maximal secant sequence for AA. Now prove that one has the inequality ex(A)⩽long(A/x)e_x(A) \leqslant \mathrm{long}(A/x) and that equality occurs only if the homomorphism (A/x)[T1,...,Td]→φgrx(A)(A/x)[T_1, ..., T_d] \xrightarrow{\varphi} \mathrm{gr}_x(A) defined by φ(Ti)=ξi\varphi(T_i) = \xi_i, where ξi\xi_i is the class of xix_i modulo x2x^2, is an isomorphism (which means that (x1,...,xd)(x_1, ..., x_d) is completely secant).

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.