Bourbaki

Exercise 21, § 7

Commutative Algebra, VIII, p. 107

Let AA and A’A’ be two noetherian rings, and let q (resp. q’) be an ideal of AA (resp. A’A’) contained in the radical of AA (resp. A’A’) and such that long(A/q) (resp. long(A’/q’)) is finite. Let Ω\Omega be the ideal q⊗A′+A⊗q′q \otimes A' + A \otimes q' of the ring A⊗ZA′A \otimes_Z A'. Prove that it is contained in the radical of A⊗ZA′A \otimes_Z A' and that one has the equality

eΩ(A⊗ZA′)=eq(A).eq′(A′). e_\Omega(A \otimes_Z A') = e_q(A).e_{q'}(A').
Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.