Bourbaki

Exercise 3, § 7

Commutative Algebra, VIII, p. 103

Let kk be a field, and let f1,...,frf_1, ..., f_r be homogeneous elements of the graded ring k[X1,...,Xn]k[X_1, ..., X_n] forming a completely transversal sequence. We shall say that the quotient ring

H=k[X1,...,Xn]/(f1,...,fr) H = k[X_1, ..., X_n]/(f_1, ..., f_r)
is a graded ring of complete intersection. Let II be a nonzero graded ideal of the ring H=k[X1,...,Xn]/(f1,...,fr)H = k[X_1, ..., X_n]/(f_1, ..., f_r) endowed with the quotient grading. Now prove that one has dim⁡(I)=dim⁡(H)\dim(I) = \dim(H). Deduce that one has either dim⁡(H/I)<dim⁡(H)\dim(H/I) < \dim(H), or dim⁡(H/I)=dim⁡(H)\dim(H/I) = \dim(H) and cM/I<cMc_{M/I} < c_M (§ 4, n° 2). (One will consider the ideal bb formed by the s∈Hs \in H such that s.I={0}s.I = \{0\} and one will prove that if one has dim⁡(I)<dim⁡(H)\dim(I) < \dim(H), then bb contains a nonzero divisor element, by examining the position of bb with respect to the minimal prime ideals of HH and to H+=H≥1H_+ = H_{\geq 1}.)

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