Bourbaki

Exercise 7, § 7

Commutative Algebra, VIII, p. 104

Let AA be a local ring, with maximal ideal mm, MM a finitely generated AA-module, (x1,...,xd)(x_1, ..., x_d) a sequence of elements of mm secant for the AA-module MM, and xx the ideal x1A+⋯+xdAx_1 A + \cdots + x_d A.

a) Suppose the AA-module MM is faithful. Then the quotient of gr⁡x(A)\operatorname{gr}_x(A) by its nilradical nn is isomorphic to (A/m)[X1,...,Xd](A/m)[X_1, ..., X_d] and (gr⁡x(M))n(\operatorname{gr}_x(M))_n is a (gr⁡x(A))n(\operatorname{gr}_x(A))_n-module of length ex(M)e_x(M).

b) In the general case, gr⁡x(A)\operatorname{gr}_x(A) possesses a unique minimal prime ideal nn and (gr⁡x(M))n(\operatorname{gr}_x(M))_n is a gr⁡x(A)\operatorname{gr}_x(A)-module of length ex(M)e_x(M).

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.