Bourbaki

Exercise 5, § 2

Commutative Algebra, X, p. 154

Bourbaki marks this one as harder than the rest.

Let AA be a noetherian local ring, MM a finitely generated a-module, x=(x1,…,xn)x = (x_1, \ldots, x_n) a sequence of elements of mA\mathfrak{m}_A, generating an ideal xx; suppose that the a-module M/xMM/xM is of finite length (which implies n⩾dim⁡(M)n \geqslant \dim(M)). We denote by gr(A) and gr(M) the associated graded modules of A and M for the x-adic topology, ξi\xi_i (1⩽i⩽n1 \leqslant i \leqslant n) the image of xix_i in x/x2x/x^2, ξ\xi the sequence (ξ1,…,ξn)(\xi_1, \ldots, \xi_n). a) For p∈Zp \in \mathbf{Z}, put FpKi(x,M)=Ki(x,xp−iM)F^p K_i(x, M) = K_i(x, x^{p-i}M) (with the convention xs=Ax^s = A for s⩽0s \leqslant 0). Prove that FpK∙(x,M)F^p K_\bullet(x, M) is a subcomplex of K∙(x,M)K_\bullet(x, M), and that the complex ⨁pFpK∙(x,M)/Fp+1K∙(x,M)\bigoplus_p F^p K_\bullet(x, M)/F^{p+1} K_\bullet(x, M) is identified with K∙gr⁡(A)(ξ,gr⁡(M))K_{\bullet}^{\operatorname{gr}(A)}(\xi, \operatorname{gr}(M)). b) For every complex of A-modules C such that H(C)H(C) is of finite length, put χ(C)=∑i(−1)ilg⁡(Hi(C))\chi(C) = \sum_i (-1)^i \lg(H_i(C)). Prove that there exists an integer p0p_0 such that the complex

FpK∙(x,M)/Fp+1K∙(x,M)F^p K_\bullet(x, M)/F^{p+1} K_\bullet(x, M) has zero homology for p⩾p0p \geqslant p_0; deduce the equalities

χ(K∙gr(A)(ξ,gr(M)))=χ(K∙(x,M)/FpK∙(x,M))=∑(−1)i(ni)lg⁡(M/xp−iM) \chi(K_{\bullet}^{\mathrm{gr}(A)}(\xi, \mathrm{gr}(M))) = \chi(K_\bullet(x, M)/F^p K_\bullet(x, M)) = \sum (-1)^i \binom{n}{i} \lg(M/x^{p-i}M)

for p⩾p0p \geqslant p_0.

c) Prove that the expression above is zero if n>dim⁡(M)n > \dim(M), and equal to cx(M)c_x(M) if n=dim⁡(M)n = \dim(M).

d) Let h⩾0h \geqslant 0, and p⩾p0p \geqslant p_0; prove that the canonical injection of FpK∙(x,M)F^p K_\bullet(x, M) into Fp+hK∙(x,M)F^{p+h} K_\bullet(x, M) is a homology equivalence. Deduce that Hi(FpK∙(x,M))H_i(F^p K_\bullet(x, M)) is discrete for the x-adic topology. Prove moreover that the filtration of this module defined by the images of the mappings Hi(Fp+hK∙(x,M))→Hi(FpK∙(x,M))H_i(F^{p+h} K_\bullet(x, M)) \to H_i(F^p K_\bullet(x, M)) is x-good, and deduce that FpK∙(x,M)F^p K_\bullet(x, M) has zero homology. Conclude that χ(K∙(x,M))\chi(K_\bullet(x, M)) is zero if n>dim⁡(M)n > \dim(M), and equal to ex(M)e_x(M) if n=dim⁡(M)n = \dim(M).

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.