Bourbaki

Exercise 1, § 3

Commutative Algebra, X, p. 157

Let ρ:A→B\rho : A \to B be a local homomorphism of noetherian local rings, NN a finitely generated BB-module. We suppose that the AA-modules BB and NN are flat.

a) Prove the equality dpB(N)=dpκA⊗AB(κA⊗AN)dp_B(N) = dp_{\kappa_A \otimes_A B}(\kappa_A \otimes_A N) (consider a resolution of NN by finitely generated free BB-modules).

b) Let MM be a finitely generated AA-module. Prove the equality

dpB(M⊗AN)=dpA(M)+dpB(N) dp_B(M \otimes_A N) = dp_A(M) + dp_B(N)

(Let KK (resp. LL) be a resolution of the AA-module MM (resp. of the BB-module NN) by finitely generated free modules; prove that K⊗ALK \otimes_A L is a resolution of M⊗ANM \otimes_A N by free BB-modules. If dpA(M)=mdp_A(M) = m and dpB(N)=ndp_B(N) = n, calculate Hm+n(κB⊗B(K⊗AL))H_{m+n}(\kappa_B \otimes_B (K \otimes_A L)) in terms of Hm(κA⊗AK)H_m(\kappa_A \otimes_A K) and Hn(κB⊗BL)H_n(\kappa_B \otimes_B L).)

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.