Bourbaki

Exercise 15, § 3

Commutative Algebra, X

Let AA be a local ring noetherian, MM a AA-module finitely generated and of finite injective dimension.

a) Let p∈Supp⁡(M)p \in \operatorname{Supp}(M). Prove the equality prof⁡(A)=prof⁡(Ap)+dim⁡(A/p)\operatorname{prof}(A) = \operatorname{prof}(A_p) + \dim(A/p). (Put p=prof⁡(Ap)p = \operatorname{prof}(A_p) and q=dim⁡(A/p)q = \dim(A/p); observe that one has p=di⁡Ap(Mp)p = \operatorname{di}_{A_p}(M_p), whence Ext⁡App(κ(p),Mp)≠0\operatorname{Ext}^{p}_{A_p}(\kappa(p), M_p) \neq 0 and consequently Ext⁡Ap+q(κA,M)≠0\operatorname{Ext}^{p+q}_{A}(\kappa_A, M) \neq 0 by Lemma 3 of § 1, No. 7, which entails prof⁡(A)=di⁡A(M)=p+q.\operatorname{prof}(A) = \operatorname{di}_A(M) = p + q .) If Supp⁡(M)=Spec⁡(A)\operatorname{Supp}(M) = \operatorname{Spec}(A), AA is a Macaulay ring.

b) Prove the equality grade⁡(M)+dim⁡(M)=prof⁡(A)\operatorname{grade}(M) + \dim(M) = \operatorname{prof}(A) (use a) and Exercise 15 of § 1).

Solution

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