Bourbaki

Exercise 10, § 5

Commutative Algebra, X, p. 168

Let AA be a discrete valuation ring, vv its normalized valuation, KK its field of fractions. Let us consider a noetherian AA-algebra BB endowed with a homomorphism of AA-algebras ε:B→A\varepsilon : B \to A. We denote by II the kernel of ε\varepsilon, and by JJ its annihilator in BB.

(a) Prove that the following conditions are equivalent: (i) the AA-module I/I2I/I^2 is of finite length ; (ii) the local ring of K⊗ABK \otimes_A B at the maximal ideal K⊗AIK \otimes_A I is isomorphic (as a KK-algebra) to KK ; (iii) one has K⊗AB=(K⊗AI)⊕(K⊗AJ)K \otimes_A B = (K \otimes_A I) \oplus (K \otimes_A J).

We now suppose that these conditions are satisfied ; we denote by γ(B,ε)\gamma(B, \varepsilon), or simply γ(B)\gamma(B), the length of the AA-module I/I2I/I^2, and by η(B,ε)\eta(B, \varepsilon), or simply η(B)\eta(B), that of the AA-module A/ε(J)A/\varepsilon(J).

(b) Let bb be an ideal of BB contained in II ; we consider the AA-algebra B′=B/bB' = B/b and the homomorphism ε′:B′→A\varepsilon' : B' \to A deduced from ε\varepsilon. Prove that B′B' also satisfies the conditions of (a), and that one has γ(B′,ε′)≤γ(B,ε)\gamma(B', \varepsilon') \leq \gamma(B, \varepsilon) and η(B′,ε′)≤η(B,ε)\eta(B', \varepsilon') \leq \eta(B, \varepsilon).

(c) Suppose that the AA-module BB is free of finite type. Prove that JJ is a free AA-module of rank one, a direct factor in BB, and that one has TrB/A(x)=ε(x)\mathrm{Tr}_{B/A}(x) = \varepsilon(x) for all x∈Jx \in J.

(d) Suppose moreover that BB is a Gorenstein ring ; denote by ℓ\ell a basis of the BB-module B∗B^* (§ 3, exerc. 5), and by δ\delta a generator of the different ideal of BB over AA (exerc. 7, b)). Prove the equality η(B)=v(ε(δ))\eta(B) = v(\varepsilon(\delta)) (prove that ℓ(J)\ell(J) is equal to AA, and use (c)).

e) We place ourselves in the situation of b), with b≠0b \neq 0 ; we suppose that the AA-algebras BB and B′B' are finite and flat, and that BB is a Gorenstein ring. Prove that one has η(B′)<η(B)\eta(B') < \eta(B) (observe that the image of JJ in B/mABB/m_A B is the socle of B/mABB/m_A B, hence is contained in b/mAbb/m_A b).

Solution

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Machine translation of the English, by gpt-5-6, gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.