Exercise 11, § 5
Commutative Algebra, X, p. 168
Bourbaki marks this one as harder than the rest.
We retain the notations of the preceding exercise; we suppose that the rings and are local and complete.
a) Now prove that is isomorphic to the quotient of an algebra of formal series by an ideal contained in ; one can take , where is the image of in .
b) Prove that the following conditions are equivalent: (i) is a finite and flat -algebra and a complete intersection ring ; (ii) the ideal is generated by a sequence completely transverse for . (cf. exerc. 5.)
c) If these conditions are satisfied, prove that one has (use exerc. 9 and 10, d)).
d) Now prove that one can find a sequence of elements of completely transverse for such that the -algebra satisfies .
(Deduce from the exact sequence (A, III, p. 137) an exact sequence of -modules ; take elements of whose images in form a basis over of the image of .)
e) Deduce using exerc. 10, e) that one has and that equality holds if and only if is a complete intersection ring.
Solution
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