Bourbaki

Exercise 2, § 5

Commutative Algebra, X

Let A be a regular local ring, I an ideal of A.

a) If ht(I)=1\mathrm{ht}(I) = 1, prove that the following conditions are equivalent : (i) the ideal I is principal ; (ii) A/IA/I is a Gorenstein ring ; (iii) A/IA/I is a Macaulay ring. b) Suppose ht(I)=2\mathrm{ht}(I) = 2; in order that A/IA/I be a Gorenstein ring, it is necessary and sufficient that the ideal I be a complete intersection (if (L,p)(L,p) is a minimal projective resolution of I, observe that L1L_1 is of rank 1 and consequently L0L_0 of rank 2). c) Let kk be a commutative field ; take A=k[[X,Y,Z]]A = k[[X,Y,Z]] and I=(XY,YZ,ZX,X2−Y2,Y2−Z2)I = (XY, YZ, ZX, X^2 - Y^2, Y^2 - Z^2). Prove that I is an ideal of height 3 which is not a complete intersection, and that A/IA/I is a Gorenstein ring.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.