Bourbaki

Exercise 6, § 5

Commutative Algebra, X, p. 166

Bourbaki marks this one as harder than the rest.

Let AA be a local noetherian ring, II an ideal of AA. a) Prove that the following conditions are equivalent: (i) the ideal II is a complete intersection; (ii) the A/IA/I-module I/I2I/I^2 is free and one has dpA(A/I)<+∞dp_A(A/I) < +\infty. (Under assumption (ii), deduce from exerc. 2 of § 3 that there exists a cancellable element x in II such that x∉mAIx \not\in m_A I; reason by induction on the dimension of I/I2I/I^2.) b) Prove that the set of prime ideals pp of AA where the ideal IpI_p is a complete intersection is open in Spec(A)\mathrm{Spec}(A). c) Let BB be a presentable ring; prove that the set of prime ideals q of BB such that BqB_q is a complete intersection ring is open in Spec(B)\mathrm{Spec}(B).

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.