Exercise 6, § 5
Commutative Algebra, X, p. 166
Bourbaki marks this one as harder than the rest.
Let be a local noetherian ring, an ideal of . a) Prove that the following conditions are equivalent: (i) the ideal is a complete intersection; (ii) the -module is free and one has . (Under assumption (ii), deduce from exerc. 2 of § 3 that there exists a cancellable element x in such that ; reason by induction on the dimension of .) b) Prove that the set of prime ideals of where the ideal is a complete intersection is open in . c) Let be a presentable ring; prove that the set of prime ideals q of such that is a complete intersection ring is open in .
Solution
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