Bourbaki

Exercise 7, § 5

Commutative Algebra, X, p. 167

Let AA be a ring, BB an AA-algebra; suppose that the AA-module BB is free of finite type. In the following exercises, we denote by B∗B^* the AA-module HomA(B,A)\mathrm{Hom}_A(B, A), and we equip it with its natural structure of BB-module. (a) Let (ei)i∈I(e_i)_{i \in I} be a basis of the AA-module BB, and (ei∗)i∈I(e_i^*)_{i \in I} the dual basis of B∗B^*. Prove that the element TrB/A\mathrm{Tr}_{B/A} of B∗B^* (A, III, p. 110) is equal to ∑ieiei∗\sum_i e_i e_i^*. (b) Suppose that the BB-module B∗B^* is free of rank 1; let ℓ\ell be an element forming a basis of this module, and let δ\delta be the element of BB such that TrB/A=δℓ\mathrm{Tr}_{B/A} = \delta \ell. The ideal δB\delta B of BB does not depend on the choice of ℓ\ell; it is called the different ideal of BB over AA. Prove that NB/A(δ)N_{B/A}(\delta) is a generator of the discriminant ideal of BB over AA (A, III, p. 115; calculate the discriminant of a basis (ei)(e_i) of BB over AA using the matrix of the multiplication by δ\delta in this basis).

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.