Bourbaki

Exercise 9, § 5

Commutative Algebra, X, p. 167

Let AA be a ring, nn an integer, SS the algebra A[X1,…,Xn]A[X_1, \ldots, X_n] (resp. A[[X1,…,Xn]]A[[X_1, \ldots, X_n]]), aa an ideal of SS generated by a sequence P=(P1,…,Pn)P = (P_1, \ldots, P_n) completely transversal for SS. Put B=S/aB = S/a, and denote by π\pi the canonical homomorphism of SS onto S/aS/a. Suppose that the AA-module BB is free of finite type. We propose to prove that the BB-module B∗B^* is free of rank 1 and that the different ideal of BB over AA is generated by π(det⁡(∂Pi∂Xj))\pi(\det(\frac{\partial P_i}{\partial X_j})). (a) Put C=S⊗ABC = S \otimes_A B and ξi=Xi⊗1−1⊗π(Xi)\xi_i = X_i \otimes 1 - 1 \otimes \pi(X_i) for 1≤i≤n1 \leq i \leq n. Denote by φ:C→B\varphi : C \to B the homomorphism of AA-algebras such that φ(P⊗b)=π(P)b\varphi(P \otimes b) = \pi(P)b. Prove that the kernel of φ\varphi is generated by the sequence ξ=(ξ1,…,ξn)\xi = (\xi_1, \ldots, \xi_n), and that this sequence is completely transversal for CC. (b) Let (cij)∈Mn(C)(c_{ij}) \in M_n(C) be a matrix satisfying Pi⊗1=∑jcijξjP_i \otimes 1 = \sum_j c_{ij} \xi_j. Prove the equality π(∂Pi∂Xj)=φ(cij)\pi(\frac{\partial P_i}{\partial X_j}) = \varphi(c_{ij}). (c) The matrix (cij)(c_{ij}) defines a morphism of complexes K∙(P,C)→K∙(ξ,C)K_\bullet(P, C) \to K_\bullet(\xi, C) (A, X, p. 151), whence a morphism of complexes of SS-modules u:K∙(P,S)→K∙(ξ,C)u : K_\bullet(P, S) \to K_\bullet(\xi, C). The homomorphism un:S→Cu_n : S \to C maps 1S1_S onto the element d=det⁡(cij)d = \det(c_{ij}) of CC. (d) Let v:HomS(C,S)⊗CB→Bv : \mathrm{Hom}_S(C, S) \otimes_C B \to B be the BB-linear homomorphism such that v(f⊗1)=π(f(d))v(f \otimes 1) = \pi(f(d)); prove that vv is an isomorphism (identify vv with Hn(HomS(u,1S))H^n(\mathrm{Hom}_S(u, 1_S))), and observe that each of the complexes K∙(P,S)K_\bullet(P, S) and K∙(ξ,C)K_\bullet(\xi, C) defines a resolution of BB by free SS-modules of finite type. (e) Consider the composite mapping t:HomA(B,A)→HomS(C,S)→Bt : \mathrm{Hom}_A(B, A) \to \mathrm{Hom}_S(C, S) \to B, where the first arrow is obtained by extension of scalars and the second is deduced from vv. Prove that tt is BB-linear and bijective (identify HomS(C,S)\mathrm{Hom}_S(C, S) with HomA(B,A)⊗BC\mathrm{Hom}_A(B, A) \otimes_B C). (f) Prove the formula t(TrB/A)=φ(d)t(\mathrm{Tr}_{B/A}) = \varphi(d) (express dd and TrB/A\mathrm{Tr}_{B/A} using a basis of BB and the dual basis of B∗B^*, cf. exerc. 7, a)).

g) Deduce from b), e) and f) that the different ideal of B over A is generated by π(det⁡(∂Pi∂Xj))\pi(\det(\frac{\partial P_i}{\partial X_j})).

Solution

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Machine translation of the English, by gpt-5-mini, gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.