Bourbaki

Exercise 10, § 7

Commutative Algebra, X, p. 172

Bourbaki marks this one as harder than the rest.

Let AA be a complete noetherian local ring, KK its field of fractions. Let p\mathfrak{p} be a prime ideal of AA; denote by BB the local ring ApA_\mathfrak{p} and by B^\widehat{B} its completion. a) Suppose that AA is regular and that KK has characteristic zero. Now prove that the KK-algebra K⊗BB^K \otimes_B \widehat{B} is absolutely regular. b) Suppose that AA is regular and that KK has characteristic p>0p > 0, so that AA is identified with a formal power series ring k[[T1,…,Tn]]k[[T_1, \ldots, T_n]] (IX, § 3, No. 3, Theorem 2). Denote by (kλ)λ∈A(k_\lambda)_{\lambda \in A} the family of subfields kλk_\lambda of kk containing kpk^p and such that kk is a finite degree extension of kλk_\lambda. Let λ∈A\lambda \in A; denote by AλA_\lambda the ring kλ[[T1p,…,Tnp]]k_\lambda[[T_1^p, \ldots, T_n^p]], by BλB_\lambda the local ring of AλA_\lambda at the prime ideal p∩Aλ\mathfrak{p} \cap A_\lambda, and by KλK_\lambda the field of fractions of AλA_\lambda and BλB_\lambda. Prove that the AA-algebra BB (endowed with the discrete topology) is formally smooth relative to BλB_\lambda (one may first prove that B^\widehat{B} is isomorphic to B⊗BλBλ^B \otimes_{B_\lambda} \widehat{B_\lambda}). c) Under the hypotheses of bb), prove that every local ring of K⊗BB^K \otimes_B \widehat{B} is of the form (B^)r(\widehat{B})_r, with r∈Spec(B^)r \in \mathrm{Spec}(\widehat{B}) and r∩B={0}r \cap B = \{0\}, and that it is formally smooth over KK relative to KλK_\lambda. Deduce that the KK-algebra K⊗BB^K \otimes_B \widehat{B} is absolutely regular (prove that the family {Kλ}λ∈A\{K_\lambda\}_{\lambda \in A} of subfields of KK is filtrante decreasing and that ⋂λ∈AKλ=kp((T1,…,Tn))\bigcap_{\lambda \in A} K_\lambda = k^p((T_1, \ldots, T_n))); then apply exercise 9). d) Return to the general case. Prove that AA is a Grothendieck ring (§ 6, exercise 5); if q∈Spec(B)q \in \mathrm{Spec}(B), it is a matter of proving that the κ(q)\kappa(q)-algebra κ(q)⊗BB^\kappa(q) \otimes_B \widehat{B} is absolutely regular; replacing AA by A/(A∩q)A/(A \cap q), one may suppose that AA is integral and q={0}q = \{0\}; one will use IX, § 2, No. 3, Theorem 3 and § 3, No. 3, Theorem 2 to reduce to the case where AA is a complete regular local ring.

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.