Bourbaki

Exercise 11, § 7

Commutative Algebra, X, p. 172

Let AA be a noetherian ring; suppose that for every maximal ideal mm of AA, the completion of the local ring AmA_m is an absolutely regular AmA_m-algebra. Now prove that AA is a Grothendieck ring (§ 6, exerc. 5). (One will use loc. cit. and the preceding exercise to show that for every maximal ideal mm of AA, the ring AmA_m is a Grothendieck ring.)

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.