Bourbaki

Exercise 10, § 8

Commutative Algebra, X

Let AA be a noetherian ring, M,P,TM, P, T be AA-modules; suppose that MM is of finite type, TT of finite injective dimension, and that the modules ExtAi(M,P)\mathrm{Ext}_A^i(M, P) and ExtAi(P,T)\mathrm{Ext}_A^i(P, T) are zero for i>0i > 0. Prove that the canonical homomorphism M⊗AHomA(P,T)→HomA(HomA(M,P),T)M \otimes_A \mathrm{Hom}_A(P, T) \to \mathrm{Hom}_A(\mathrm{Hom}_A(M, P), T) which maps m⊗hm \otimes h to the homomorphism u↦h(u(m))u \mapsto h(u(m)) is an isomorphism (reason as in the proof of the prop. 6, replacing JJ by an injective resolution of TT).

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.