Bourbaki

Exercise 23, § 7

Algebra, I

Let FF be a free group with basic family (x,y)(x, y) with x≠yx \neq y. Now prove that the derived group of FF has as basic family the family of commutators (xi,yj)(x^i, y^j) for i∈Z,j∈Z,i≠0,j≠0i \in \mathbf{Z}, j \in \mathbf{Z}, i \neq 0, j \neq 0. (Use Exercise 20 or I, p. 149, Exercise 32.)

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.