Bourbaki

Exercise 23, § 7

Algebra, I, 165

Let F be a free group with basic family (x,y),x≠y(x, y), x \neq y. Show that the derived group of F has as basic family the family of commutators (xi,yj),i∈Z,j∈Z,i≠0,j≠0.(x^i, y^j), i \in \mathbf{Z}, j \in \mathbf{Z}, i \neq 0, j \neq 0. (Use Exercise 20 or Exercise 32.)

Solution

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