Bourbaki

Exercise 6, § 2

Algebra, II, p. 183

a) If E is an A-module, every injective endomorphism u of E is not a left divisor of zero in the ring EndA(E)\mathrm{End}_A(E). Conversely, if for every sub-A-module F≠{0}F \neq \{0\} of E there exists an endomorphism v≠0v \neq 0 of E such that v(E)⊂Fv(E) \subset F, an element which is not a left divisor of zero in EndA(E)\mathrm{End}_A(E) is an injective endomorphism. The preceding condition is satisfied if there exists a linear form x′∈E∗x' \in E^* and an x∈Ex \in E such that ⟨x,x′⟩\langle x, x' \rangle is invertible in A and in particular if E is free. b) Every endomorphism ≠0\neq 0 of the Z\mathbf{Z}-module Q\mathbf{Q} is bijective, although there exists no linear form ≠0\neq 0 on Q\mathbf{Q}. c) Let UpU_p be the Z\mathbf{Z}-module defined in II, p. 180, exerc. 12 d). Show that the endomorphism x↦pxx \mapsto px of UpU_p is not injective and is not a left divisor of zero in EndZ(Up)\mathrm{End}_{\mathbf{Z}}(U_p).

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.