Bourbaki

Exercise 7, § 9

Algebra, II, p. 201

Bourbaki marks this one as harder than the rest.

Let E (resp. E’) be a finite-dimensional affine space n≥2n \geq 2 over a field K having at least 3 elements (resp. over a field K’), and let uu be an injective mapping of E into E’ transforming any three points on a straight line of E into three points on a straight line, and such that the affine linear variety generated by u(E)u(E) in E’ is equal to E’. (a) Now prove that uu transforms every system of affinely independent points of E into a system of affinely independent points (use Exercise 5 of II, p. 200). (b) Let D1,D2D_1, D_2 be two parallel lines in E, D1′,D2′D'_1, D'_2 the lines of E’ containing respectively u(D1)u(D_1) and u(D2)u(D_2). Now prove that D1′D'_1 and D2′D'_2 are in the same plane; if moreover uu is surjective, now prove that D1′D'_1 and D2′D'_2 are parallel (in the contrary case, now prove that there would be 3 points not on a straight line of E whose images by uu would be on a straight line) (cf. II, p. 204, Exercise 17). (c) Suppose henceforth that if D1D_1 and D2D_2 are parallel lines of E, the lines of E’ containing respectively u(D1)u(D_1) and u(D2)u(D_2) are parallel. Now prove that if one takes in E an origin aa and in E’ the origin a′=u(a)a' = u(a), there exists an isomorphism σ\sigma of K onto a subfield K1K_1 of K’, such that if E is considered as a vector space over K and E’ as a vector space over K1K_1, uu is a semilinear injective mapping (relative to σ\sigma) of E into E’ (II, p. 32). (First consider the case n=2n = 2; given a basis (e1,e2)(e_1, e_2) of E, now prove that for any two elements α,β\alpha, \beta of K, one can construct the points (α+β)e1(\alpha + \beta)e_1 and (αβ)e1(\alpha\beta)e_1 of E from the points 0,e1,e2,αe1,βe10, e_1, e_2, \alpha e_1, \beta e_1 by constructions of parallels to given lines and intersections of given lines; deduce that one can write u(λe1)=λσu(e1)u(\lambda e_1) = \lambda^\sigma u(e_1), where σ\sigma is an isomorphism of K onto a subfield of K’, then show that one also has u(λe2)=λσu(e2)u(\lambda e_2) = \lambda^\sigma u(e_2) by considering the line joining the points λe1\lambda e_1 and λe2\lambda e_2. Finally pass from there to the case where nn is arbitrary, by reasoning by induction on nn.) If uu is bijective, now prove that K1=K′K_1 = K'. (d) Extend the result of c) to the case where K is a field with 2 elements by supposing in addition that uu transforms every system of affinely independent points of E into a system of affinely independent points of E’.

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.