Bourbaki

Exercise 27, § 11

Algebra, III, p. 202

Let B be an associative unital algebra over a commutative field K, and let m:B⊗KB→Bm : B \otimes_K B \to B be the K-linear mapping defining the multiplication in B. The tensor product B∗⊗KB∗B^* \otimes_K B^* (where B∗B^* is the dual vector space of the vector space B) is canonically identified with a vector subspace of (B⊗KB)∗(B \otimes_K B)^* (II, p. 110, prop. 16).

a) Now prove that, for an element w∈B∗w \in B^*, the following conditions are equivalent: 1∘ tm(w)∈B∗⊗B∗;2∘1^\circ \ ^t m(w) \in B^* \otimes B^* ; 2^\circ the set of the x⋅wx \cdot w, where x runs through B, is a finite-dimensional subspace of B∗;3∘B^* ; 3^\circ the set of the w⋅xw \cdot x, where x runs through B, is a finite-dimensional subspace of B∗;4∘B^* ; 4^\circ the set of the x⋅w⋅yx \cdot w \cdot y, where x and y run through B, is contained in a finite-dimensional subspace of B∗B^*.

b) Let B′⊂B∗B' \subset B^* be the set of the w∈B∗w \in B^* satisfying the equivalent conditions of a). Now prove that tm(B′)⊂B′⊗KB′^t m(B') \subset B' \otimes_K B'. (For w∈B′w \in B', write tm(w)=∑iui⊗vi^t m(w) = \sum_i u_i \otimes v_i, where for example the uiu_i are linearly independent in B∗B^*; now prove that one then has vi∈B′v_i \in B' for every i by using the associativity of B, and reasoning by contradiction.) B′B' is therefore the largest cogebra contained in B∗B^*, for which tm^t m is the coproduct. One says that B′B' is the dual cogebra of the algebra B. When B is of finite dimension, B′=B∗B' = B^*.

c) Now prove that if B is a commutative field of infinite dimension over K, one has B′={0}B' = \{0\}. (Note that the orthogonal of the set of the x⋅wx \cdot w, for a w∈B∗w \in B^*, x running through B, is an ideal of B).

d) Let B1,B2B_1, B_2 be two K-algebras, f:B1→B2f : B_1 \to B_2 a K-homomorphism of algebras. Now prove that one has tf(B2′)⊂B1′^t f(B'_2) \subset B'_1, and that tf^t f, restricted to B2′B'_2, is a homomorphism of cogebras of B2′B'_2 into B1′B'_1.

e) If C is a coassociative and co-unital cogebra over K, the canonical injection C → C** of the vector space C into its bidual transforms C into a subspace of (C*)′, dual cogebra of the dual algebra C* of C, and is a homomorphism of cogebras of C into (C*)′.

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.