Bourbaki

Exercise 8, § 2

Tag 06BF, permanent. Cite it as [Bourbaki, Tag 06BF].

Algebra, IV, p. 84

Let BB be the additive group Z⊕(Z/2Z)\mathbf{Z} \oplus (\mathbf{Z}/2\mathbf{Z}). We endow it with a commutative ring structure by setting (a,b).(a′,b′)=(aa′,ab′+ba′)(a, b).(a', b') = (aa', ab' + ba') for (a,b)∈B(a, b) \in B and (a′,b′)∈B(a', b') \in B. Let ε=(0,1)∈B\varepsilon = (0, 1) \in B. Let f(X)=εX(X−1)∈B[X]f(X) = \varepsilon X(X - 1) \in B[X]. Then f(α)=0f(\alpha) = 0 for every α∈B\alpha \in B.

Solution

No solution has been written yet.

Cited by

Nothing.

Cites

Nothing.

Translated with machine help, not yet reviewed by a person.