Bourbaki

Exercise 18, § 2

Algebra, X, p. 177

Let EE be a spectral sequence (exercise 14), such that the AA-module E2E_2 is of finite length. Let χ\chi be the set of classes of AA-modules of finite length; now prove that one has χ(Er)=χ(E2)=χ(E∞)\chi(E_r)=\chi(E_2)=\chi(E_\infty) for every r≥2r\geq2 (X, p. 41). If moreover EE converges towards an AA-module graded GG, the latter is of finite length and one has χ(G)=χ(E∞)\chi(G)=\chi(E_\infty).

☡19) A simplicial scheme is called a pair (K,F)(K,\mathscr F), where KK is a set and F\mathscr F a set of finite subsets of KK, called faces of KK, such that every subset of a face is a face and every point of KK belongs to at least one face. A simplicial mapping of a simplicial scheme (K,F)(K,\mathscr F) into a simplicial scheme (L,G)(L,\mathscr G) is a mapping from KK into LL which transforms every face of KK into a face of LL.

a) Let nn be an integer ≥0\geq0. An nn-simplex of the simplicial scheme KK is called every sequence (α0,…,αn)(\alpha_0,\ldots,\alpha_n) of elements of KK such that the αi\alpha_i belong to one and the same face of KK. We denote by Sn(K,A)S_n(K,A) the free AA-module generated by the nn-simplices for n≥0n\geq0, and we set Sn(K,A)=0S_n(K,A)=0 for n<0n<0. We define an AA-homomorphism

dn:Sn(K,A)→Sn−1(K,A) d_n:S_n(K,A)\rightarrow S_{n-1}(K,A)

by setting dn=0d_n=0 for n≤0n\leq0 and

dn(α0,…,αn)=∑i=0n(−1)i(α0,…,αi^,…,αn) d_n(\alpha_0,\ldots,\alpha_n)=\sum_{i=0}^{n}(-1)^i(\alpha_0,\ldots,\widehat{\alpha_i},\ldots,\alpha_n)

for every nn-simplex (α0,…,αn)(\alpha_0,\ldots,\alpha_n) (the sign  ^\widehat{\ } over a letter means that it is to be omitted). Now prove that dn−1∘dn=0d_{n-1}\circ d_n=0 for every nn, so that (S(K,A),d)(S(K,A),d) is a complex of AA-modules. One defines analogously an AA-complex C(K,A)C(K,A) by setting Cn(K,A)=Hom⁡A(Sn(K,Z),A)C^n(K,A)=\operatorname{Hom}_A(S_n(K,\mathbf Z),A), δn=Hom⁡(dn+1,1A)\delta^n=\operatorname{Hom}(d_{n+1},1_A) for every nn. For n≥0n\geq0, one sometimes denotes by Hn(K,A)H_n(K,A) (resp. Hn(K,A)H^n(K,A)) the AA-module Hn(S(K,A))H_n(S(K,A)) (resp. Hn(C(K,A))H^n(C(K,A))).

b) Let K,LK,L be two simplicial schemes, f:K→Lf:K\rightarrow L a simplicial application. Now prove that ff induces morphisms of complexes S(f):S(K,A)→S(L,A)S(f):S(K,A)\rightarrow S(L,A) and C(f):C(L,A)→C(K,A)C(f):C(L,A)\rightarrow C(K,A), whence AA-homomorphisms f∗:H(K,A)→H(L,A)f_*:H(K,A)\rightarrow H(L,A) and f∗:H(L,A)→H(K,A)f^*:H(L,A)\rightarrow H(K,A).

c) Let g:K→Lg:K\rightarrow L be a second simplicial application. We say that ff and gg are simplicially homotopic if, for every face σ\sigma of KK, the set f(σ)∪g(σ)f(\sigma)\cup g(\sigma) is a face of LL. Now prove that the morphisms S(f)S(f) and S(g)S(g) (resp. C(f)C(f) and C(g)C(g)) are then homotopic (define a homotopy hh by putting

h(α0,…,αn)=∑i=0n(−1)i(f(α0),…,f(αi),g(αi),…,g(αn)) h(\alpha_0,\ldots,\alpha_n)=\sum_{i=0}^{n}(-1)^i (f(\alpha_0),\ldots,f(\alpha_i),g(\alpha_i),\ldots,g(\alpha_n))

for every nn-simplex (α0,…,αn)(\alpha_0,\ldots,\alpha_n)).

d) We say that the simplicial scheme KK is conical if there exists a point ss of KK such that, for every face σ\sigma of KK, σ∪{s}\sigma\cup\{s\} is a face. Now prove that there then exist homotopisms of S(K,A)S(K,A) and of C(K,A)C(K,A) onto AA.

e) Let D(K,A)D(K,A) be the subcomplex of S(K,A)S(K,A) generated by the simplexes (α0,…,αn)(\alpha_0,\ldots,\alpha_n) for which two of the αi\alpha_i are equal, and by the elements of the form

(α0,…,αn)−ε(σ)(ασ(0),…,ασ(n)) (\alpha_0,\ldots,\alpha_n)-\varepsilon(\sigma)(\alpha_{\sigma(0)},\ldots,\alpha_{\sigma(n)})

for every nn-simplex (α0,…,αn)(\alpha_0,\ldots,\alpha_n) and every permutation σ\sigma of {0,…,n}\{0,\ldots,n\}. Now prove that D(K,A)D(K,A) is a subcomplex of S(K,A)S(K,A), and that the quotient passing application

p:S(K,A)→S(K,A)/D(K,A) p:S(K,A)\rightarrow S(K,A)/D(K,A)

is a homotopism (a reciprocal homotopism is obtained by choosing a total order on KK and associating with the class modulo D(K,A)D(K,A) of a simplex (α0,…,αn)(\alpha_0,\ldots,\alpha_n) the simplex

ε(σ)(ασ(0),…,ασ(n)) \varepsilon(\sigma)(\alpha_{\sigma(0)},\ldots,\alpha_{\sigma(n)})

where σ\sigma is the permutation such that ασ(0)<⋯<ασ(n)\alpha_{\sigma(0)}<\cdots<\alpha_{\sigma(n)} if all the αi\alpha_i are different, and 00 in the contrary case).

*20) Let RR be a complete discrete valuation ring (AC, VI, § 3, no 6), with residue field kk of characteristic p>0p>0. Suppose that the field of fractions of RR is of characteristic 00. Denote by vv the normalized valuation of R\mathbf{R}, by m\mathfrak m the maximal ideal of R\mathbf{R} and by R∗\mathbf{R}^* the multiplicative group of the units of R\mathbf{R}. For every integer n≥0n\geq 0, let R∗(n)\mathbf{R}^*(n) be the subgroup of R∗\mathbf{R}^* formed by the elements xx such that v(x−1)≥nv(x-1)\geq n.

a) Let rr be an integer, r>v(p)/(p−1)r>v(p)/(p-1). Show that the series

exp⁡(x)=∑i=0+∞xi/i! \exp(x)=\sum_{i=0}^{+\infty}x^i/i!

converges for x∈mrx\in\mathfrak m^r and defines an isomorphism of the additive group mr\mathfrak m^r onto the group R∗(r)\mathbf{R}^*(r).

b) Suppose that kk is a finite field with qq elements. Let nn be an integer ≥1\geq 1, μn\mu_n the subgroup of the elements xx of R∗\mathbf{R}^* such that xn=1x^n=1. Show that the groups μn\mu_n and R∗/(R∗)n\mathbf{R}^*/(\mathbf{R}^*)^n are finite and that one has

Card⁡(R∗/R∗n)/Card⁡(μn)=qv(n). \operatorname{Card}(\mathbf{R}^*/\mathbf{R}^{*n})/\operatorname{Card}(\mu_n)=qv(n).

(Let C\mathscr C be the set of classes of finite Z\mathbf{Z}-modules, φ:K(C)→Q∗\varphi:K(\mathscr C)\to\mathbf{Q}^* the homomorphism defined by

φ([G])=Card⁡(G)for G∈C, \varphi([G])=\operatorname{Card}(G)\quad\text{for }G\in\mathscr C,

C(r)\mathscr C^{(r)} the complex of Z\mathbf{Z}-modules such that Cp(r)=0C_p^{(r)}=0 for p≠0,1p\neq0,1, C0(r)=C1(r)=R∗(r)C_0^{(r)}=C_1^{(r)}=\mathbf{R}^*(r), d1(x)=xnd_1(x)=x^n for x∈R∗(r)x\in\mathbf{R}^*(r). Prove that φ(H(C(r)))\varphi(H(\mathscr C^{(r)})) is independent of rr, then use a.).)*

21) Suppose that the ring A is a commutative algebra over a commutative ring kk; the A-module Dk(A)D_k(A) of the kk-derivations of A is then identified with the dual of the A-module ΩA/k1\Omega^1_{A/k}, which defines on ΩA/k\Omega_{A/k} a structure of left ΛA(Dk(A))\Lambda_A(D_k(A))-module (cf. III, p. 165). Prove the formula

(X0∧⋯∧Xp)⌋dω=∑i=0p(−1)iXi((X0∧⋯∧Xi^∧⋯∧Xp)⌋ω) (X_0\wedge\cdots\wedge X_p)\rfloor d\omega = \sum_{i=0}^{p}(-1)^iX_i\bigl((X_0\wedge\cdots\wedge\widehat{X_i}\wedge\cdots\wedge X_p)\rfloor\omega\bigr)
+∑0≤i<j≤p(−1)i+j([Xi,Xj]∧X0∧⋯∧Xi^∧⋯∧Xj^∧⋯∧Xp)⌋ω \qquad+\sum_{0\leq i<j\leq p}(-1)^{i+j}\bigl([X_i,X_j]\wedge X_0\wedge\cdots\wedge\widehat{X_i}\wedge\cdots\wedge\widehat{X_j}\wedge\cdots\wedge X_p\bigr)\rfloor\omega

where ω∈ΩA/kp\omega\in\Omega^p_{A/k}, X0,…,Xp∈Dk(A)X_0,\ldots,X_p\in D_k(A), and where the sign  ^\widehat{\ } over a letter means that it is to be omitted. (Reduce to the case p=1p=1.)

22) We retain the conventions of the preceding exercise; if M is an A-module, ∇\nabla a connection on M and if X∈Dk(A)X\in D_k(A), we denote by ∇X\nabla_X the kk-endomorphism (1M⊗X)∘∇(1_M\otimes X)\circ\nabla of M.

(a) Let M1,M2M_1,M_2 be two A-modules, provided with connections 1∇,2∇{}^1\nabla,{}^2\nabla; prove that one defines a connection ∇\nabla on M1⊕M2M_1\oplus M_2 (resp. M1⊗AM2M_1\otimes_A M_2, resp. Hom⁡A(M1,M2)\operatorname{Hom}_A(M_1,M_2)) by putting ∇(m1+m2)=1∇(m1)+2∇(m2)\nabla(m_1+m_2)={}^1\nabla(m_1)+{}^2\nabla(m_2) for m1∈M1m_1\in M_1, m2∈M2m_2\in M_2 (resp. ∇X(m1⊗m2)=1∇X(m1)⊗m2+m1⊗2∇X(m2)\nabla_X(m_1\otimes m_2)={}^1\nabla_X(m_1)\otimes m_2+m_1\otimes{}^2\nabla_X(m_2) for X∈Dk(A)X\in D_k(A), m1∈M1m_1\in M_1 and m2∈M2m_2\in M_2, resp. ∇X(u)=2∇X∘u−u∘1∇X\nabla_X(u)={}^2\nabla_X\circ u-u\circ{}^1\nabla_X for X∈Dk(A)X\in D_k(A), u∈Hom⁡A(M1,M2)u\in\operatorname{Hom}_A(M_1,M_2).

(b) Let M be an A-module, ∇:M→M⊗AΩA/k1\nabla:M\to M\otimes_A\Omega^1_{A/k} a connection on M. If X,Y∈Dk(A)X,Y\in D_k(A), we denote by R(X,Y)R(X,Y) the A-endomorphism of M such that R(X,Y)(m)=⟨R(m),X∧Y⟩R(X,Y)(m)=\langle R(m),X\wedge Y\rangle for every m∈Mm\in M. Prove the formula: R(X,Y)=[∇X,∇Y]−∇[X,Y]R(X,Y)=[\nabla_X,\nabla_Y]-\nabla_{[X,Y]} (use Exercise 21).

(c) Suppose that the A-module M is projective, so that the curvature homomorphism R is identified with an element of End⁡A(M)⊗AΩA/k2\operatorname{End}_A(M)\otimes_A\Omega^2_{A/k}. If End⁡A(M)\operatorname{End}_A(M) is provided with the connection ∇\nabla defined in (a), prove that one has ∇2R=0\nabla^2R=0.

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5-mini, gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.