Bourbaki

Exercise 6, § 2

Algebra, X, p. 173

We retain the notations of Exercise 5; suppose in addition that A is commutative, that the complexes C and C’/B(C’) are flat and that there exists an ideal m of A satisfying δ(C)⊂mC\delta(C) \subset mC and ⋂n(B(C)+mnC)=B(C)\bigcap_n (B(C) + m^n C) = B(C) (* this last condition is always satisfied if A is local noetherian with maximal ideal m and if CnC_n is an A-module of finite type for every n, cf. AC, III, § 3, No. 3, prop. 6). \* Now prove that sθ−1s \theta^{-1} is a splitting of C’. (The flatness hypotheses imply Im (d+δ)∩mnC=(d+δ)(mnC)\mathrm{Im}\,(d + \delta) \cap m^n C = (d + \delta)(m^n C) for every nn; if x∈Z(C)x \in Z(C), construct by induction elements yn∈C,zn∈Z(C)∩mnCy_n \in C, z_n \in Z(C) \cap m^n C such that δ(x)=θd(yn)+δ(zn)\delta(x) = \theta d(y_n) + \delta(z_n). Conclude using Exercise 5, a).)

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.