Bourbaki

Exercise 19, § 3

Algebra, X, p. 183

We suppose that the ring AA is commutative.

a) Let (S,dS)(S, d_S) be a differential graded AA-algebra (exercise 18), MM an AA-module, u:M→Zn(S)u : M \to Z_n(S) an AA-homomorphism. Now prove that there exists on S⊗AT(M)S \otimes_A T(M) a structure of differential graded AA-algebra such that d(s⊗1)=dSs⊗1d(s \otimes 1) = d_S s \otimes 1 for s∈Ss \in S and d(1⊗m)=u(m)⊗1d(1 \otimes m) = u(m) \otimes 1 for m∈Mm \in M.

b) Let B be an A-algebra. Now prove that there exists a differential graded A-algebra S and a homomorphism of A-algebras p:S0→Bp:S_0\to B such that (S,p)(S,p) is a free resolution of the A-module B. (Construct by recurrence on nn, with the help of a), a differential graded algebra S(n)S(n), free in each degree, such that Hi(S(n))=0H_i(S(n))=0 for 0<i<n0<i<n and H0(S(n))=BH_0(S(n))=B.)

c) If the algebra B is commutative, now prove that one can find an A-algebra S alternating (III, p. 53) satisfying the conditions of b). If moreover A is noetherian and if B is a quotient of A by an ideal, now prove that one can find S in such a way that S0=AS_0=A and that SnS_n is a finitely generated A-module for every nn.

☡20) Suppose that the ring A is an algebra over a commutative ring kk. Let η:k→A\eta:k\to A be the homomorphism defined by η(λ)=λ1A\eta(\lambda)=\lambda1_A for λ∈k\lambda\in k, and let Aˉ\bar A be its cokernel. If aa is an element of A, we shall denote by aˉ\bar a its class in Aˉ\bar A. We put

Nn(A)=A⊗kAˉ⊗n⊗kA N_n(A)=A\otimes_k\bar A^{\otimes n}\otimes_k A
for n≥0n\geq0, Nn(A)=0N_n(A)=0 for n<0n<0, and
N(A)=⨁n∈ZNn(A). N(A)=\bigoplus_{n\in\mathbf Z}N_n(A).

a) Now prove that there exists a (A,A)(A,A)-endomorphism dd of N(A)N(A), graded of degree (−1)(-1), such that

d(a⊗aˉ1⊗⋯⊗aˉn⊗b)=aa1⊗aˉ2⊗⋯⊗aˉn⊗b+∑i=1n−1(−1)ia⊗⋯⊗aˉiai+1⊗⋯⊗aˉn⊗b+(−1)na⊗aˉ1⊗⋯⊗aˉn−1⊗anb d(a\otimes\bar a_1\otimes\cdots\otimes\bar a_n\otimes b) =aa_1\otimes\bar a_2\otimes\cdots\otimes\bar a_n\otimes b +\sum_{i=1}^{n-1}(-1)^i a\otimes\cdots\otimes\bar a_i a_{i+1}\otimes\cdots\otimes\bar a_n\otimes b +(-1)^n a\otimes\bar a_1\otimes\cdots\otimes\bar a_{n-1}\otimes a_nb
for a,a1,…,an,b∈Aa,a_1,\ldots,a_n,b\in A.

b) Now prove that d∘d=0d\mathbin{\circ}d=0, so that N(A)N(A) is a complex of (A,A)(A,A)-bimodules. If M is a left A-module, we denote by N(A,M)N(A,M) the A-complex N(A)⊗AMN(A)\otimes_A M.

c) Let B(A,M)B(A,M) be the standard resolution of M (X, p. 58), p:B(A,M)→N(A,M)p:B(A,M)\to N(A,M) the A-homomorphism defined by

p(a0⊗⋯⊗an⊗m)=a0⊗aˉ1⊗⋯⊗aˉn⊗m p(a_0\otimes\cdots\otimes a_n\otimes m) =a_0\otimes\bar a_1\otimes\cdots\otimes\bar a_n\otimes m
for a0,…,an∈Aa_0,\ldots,a_n\in A, m∈Mm\in M. Now prove that pp is a homotopy equivalence of A-complexes (construct by recurrence an inverse mapping up to homotopy).

*21) Let kk be a commutative ring, g\mathfrak g a kk-algebra of Lie, U its enveloping algebra (cf. LIE, I, § 2). Suppose that g\mathfrak g is a free kk-module.

(a) Now prove that there exists for every n≥0n\geq0 an injective U-homomorphism

jn:U⊗kΛn(g)→U⊗(n+1) j_n:U\otimes_k\Lambda^n(\mathfrak g)\to U^{\otimes(n+1)}
such that
jn(u⊗(x1∧⋯∧xn))=∑σ∈Snϵ(σ) u⊗xσ(1)⊗⋯⊗xσ(n) j_n\bigl(u\otimes(x_1\wedge\cdots\wedge x_n)\bigr) =\sum_{\sigma\in\mathfrak S_n}\epsilon(\sigma)\,u\otimes x_{\sigma(1)}\otimes\cdots\otimes x_{\sigma(n)}
for u∈U,x1,…,xn∈gu\in U,x_1,\ldots,x_n\in\mathfrak g.

One thus defines a graded U-homomorphism of degree 0 j:U⊗kΛ(g)→B(U,k)j:U\otimes_k\Lambda(\mathfrak g)\to B(U,k), where B(U,k)B(U,k) is the standard resolution of the left U-module kk (the structure of U-module of kk being deduced from the natural homomorphism U→kU\to k). Prove that U⊗kΛ(g)U\otimes_k\Lambda(\mathfrak g) is identified by jj with a subcomplex of B(U,k)B(U,k), the differential being given by the formula:

d(u⊗(x1∧⋯∧xn))=∑1≤i≤n(−1)i+1uxi⊗(x1∧⋯∧x^i∧⋯∧xn) d\bigl(u\otimes(x_1\wedge\cdots\wedge x_n)\bigr) = \sum_{1\leq i\leq n}(-1)^{i+1}ux_i\otimes(x_1\wedge\cdots\wedge\hat x_i\wedge\cdots\wedge x_n)
+∑1≤i<j≤n(−1)i+ju⊗([xi,xj]∧x1∧⋯∧x^i∧⋯∧x^j∧⋯∧xn) +\sum_{1\leq i<j\leq n}(-1)^{i+j}u\otimes\bigl([x_i,x_j]\wedge x_1\wedge\cdots\wedge\hat x_i\wedge\cdots\wedge\hat x_j\wedge\cdots\wedge x_n\bigr)
for u∈U,x1,…,xn∈gu\in U,x_1,\ldots,x_n\in\mathfrak g (where the sign  ^\hat{\ } on a letter means that it is to be omitted). We denote by V(g)V(\mathfrak g) the U-complex thus defined.

(b) Prove that V(g)V(\mathfrak g) defines a free resolution of the U-module kk (let (Ur)r≥0(U_r)_{r\geq0} be the natural filtration of U, FrV(g)F_rV(\mathfrak g) the sub-kk-module of V(g)V(\mathfrak g) generated by the elements up⊗xqu_p\otimes x_q for up∈Upu_p\in U_p, xq∈Λq(g)x_q\in\Lambda^q(\mathfrak g), p+q≤rp+q\leq r). Prove that FrV(g)F_rV(\mathfrak g) is a subcomplex of V(g)V(\mathfrak g), and that the complex

⨁r≥0FrV(g)/Fr−1V(g) \bigoplus_{r\geq0}F_rV(\mathfrak g)/F_{r-1}V(\mathfrak g)
is isomorphic to the complex S(g)⊗Λ(g)S(\mathfrak g)\otimes\Lambda(\mathfrak g) defined in X, p. 151). \*

Solution

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Machine translation of the English, by gpt-5-6-mini, gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.