Bourbaki

Exercise 5, § 3

Algebra, X, p. 180

a) Let 0→K→P→M→0, 0→K′→P′→M→00 \to K \to P \to M \to 0,\ 0 \to K' \to P' \to M \to 0 be two exact sequences of AA-modules, with PP and P′P' projective. Now prove that there exists a commutative diagram:

0→K⊕P′→P⊕P′→M→0↓v↓u↓lM0→P⊕K′→P⊕P′→M→0 \begin{array}{ccccccccc} 0 & \to & K \oplus P' & \to & P \oplus P' & \to & M & \to & 0 \\ & & \downarrow v & & \downarrow u & & \downarrow l_M & & \\ 0 & \to & P \oplus K' & \to & P \oplus P' & \to & M & \to & 0 \end{array}

where the horizontal lines are exact, and where uu and vv are isomorphisms (cf. 11, p. 183, exercise 4).

b) Let nn be an integer ⩾0\geqslant 0, (P,p)(P, p) and (P′,p′)(P', p') be two left resolutions of the AA-module MM, such that Pj=Pj′=0P_j = P'_j = 0 for j>nj > n and that the AA-modules PiP_i and Pi′P'_i are projective for 0⩽i⩽n−10 \leqslant i \leqslant n - 1. Now prove that the AA-modules ⨁i⩾0(P2i⊕P2i+1′)\bigoplus_{i \geqslant 0} (P_{2i} \oplus P'_{2i+1}) and ⨁j⩾0(P2j′⊕P2j+1)\bigoplus_{j \geqslant 0} (P'_{2j} \oplus P_{2j+1}) are isomorphic.

c) Under the hypotheses of b), now prove that there exist two projective complexes R,R′R, R', of null homology, such that Ri=Ri′=0R_i = R'_i = 0 for i∉[0,n]i \notin [0, n], and an isomorphism of resolutions u:P⊕R→P′⊕R′u : P \oplus R \to P' \oplus R'.

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.