Bourbaki

Exercise 2, § 5

Algebra, X, p. 187

Let M be an A-module. One says that a submodule M’ of M is pure if the complex defined by the exact sequence 0→M′→M→M/M′→00 \to M' \to M \to M/M' \to 0 is pure (exercise 1).

(a) Now prove that when A is a principal ideal domain, the notion of pure submodule coincides with that of VII, § 2, exercise 7.

(b) Suppose that the A-module M is flat. Now prove that the following conditions are equivalent:

α) the submodule M’ is pure ;

β) the quotient M/M′M/M' is flat ;

γ) for every ideal a of A, one has M′∩aM=aM′M' \cap aM = aM'.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.