Bourbaki

Exercise 7, § 5

Algebra, X, p. 187

Let CC be an AA-complex, MM an AA-module. The extension module of MM by CC (resp. of CC by MM) is called the graded kk-module

ExtA(C,M)=H(HomgrA(C,I(M)))(resp. ExtA(M,C)=H(HomgrA(L(M),C))). \mathscr{E}xt_A(C, M) = H(\mathrm{Homgr}_A(C, I(M))) \quad (\text{resp. } \mathscr{E}xt_A(M, C) = H(\mathrm{Homgr}_A(L(M), C))) .
If f:C→C′f : C \to C' is a morphism of complexes and g:M→M′g : M \to M' a homomorphism of AA-modules, one sets ExtA(f,g)=H(Homgr(f,I(g)))\mathscr{E}xt_A(f, g) = H(\mathrm{Homgr}(f, I(g))), ExtA(g,f)=H(Homgr(L(g),f))\mathscr{E}xt_A(g, f) = H(\mathrm{Homgr}(L(g), f)). a) If f:C→C′f : C \to C' is an homologism, the kk-homomorphisms ExtA(f,1)\mathscr{E}xt_A(f, 1) and ExtA(1f)\mathscr{E}xt_A(1 f) are bijective. If CC is projective and bounded on the right (resp. injective and bounded on the left), the graded kk-module ExtA(C,M)\mathscr{E}xt_A(C, M) (resp. ExtA(M,C)\mathscr{E}xt_A(M, C)) is isomorphic to H(HomgrA(C,M))H(\mathrm{Homgr}_A(C, M)) (resp. H(HomgrA(M,C))H(\mathrm{Homgr}_A(M, C))). b) Let 0→C′→C→C′′→00 \to C' \to C \to C'' \to 0 be an exact sequence of AA-complexes and 0→M′→M→M′′→00 \to M' \to M \to M'' \to 0 an exact sequence of AA-modules. Prove that there exist exact sequences
⋯→ExtAn(C′′,M)→ExtAn(C,M)→ExtAn(C′,M)→ExtAn+1(C′′,M)→⋯⋯→ExtAn(C,M′)→ExtAn(C,M)→ExtAn(C,M′′)→ExtAn+1(C,M′)→⋯⋯→ExtAn(M,C′)→ExtAn(M,C)→ExtAn(M,C′′)→ExtAn+1(M,C′)→⋯⋯→ExtAn(M′′,C)→ExtAn(M,C)→ExtAn(M′,C)→ExtAn+1(M′′,C)→⋯ \cdots \to \mathscr{E}xt_A^n(C'', M) \to \mathscr{E}xt_A^n(C, M) \to \mathscr{E}xt_A^n(C', M) \to \mathscr{E}xt_A^{n+1}(C'', M) \to \cdots \\ \cdots \to \mathscr{E}xt_A^n(C, M') \to \mathscr{E}xt_A^n(C, M) \to \mathscr{E}xt_A^n(C, M'') \to \mathscr{E}xt_A^{n+1}(C, M') \to \cdots \\ \cdots \to \mathscr{E}xt_A^n(M, C') \to \mathscr{E}xt_A^n(M, C) \to \mathscr{E}xt_A^n(M, C'') \to \mathscr{E}xt_A^{n+1}(M, C') \to \cdots \\ \cdots \to \mathscr{E}xt_A^n(M'', C) \to \mathscr{E}xt_A^n(M, C) \to \mathscr{E}xt_A^n(M', C) \to \mathscr{E}xt_A^{n+1}(M'', C) \to \cdots
c) Prove that there exists a spectral sequence "E"E (X, pp. 175-177, exercises 14 to 17) converging to ExtA(C,M)\mathscr{E}xt_A(C, M) such that "E2pq=Hq(ExtAp(C,M))"E_2^{pq} = H^q(\mathscr{E}xt_A^p(C, M)). If CC is bounded on the right, prove that there exists a spectral sequence ′E'E, converging to ExtA(C,M)\mathscr{E}xt_A(C, M), such that ′E2pq=ExtAp(Hq(C),M)'E_2^{pq} = \mathrm{Ext}_A^p(H_q(C), M) (consider the bicomplexe HomgrA(C,I(M))\mathrm{Homgr}_A(C, I(M))).

Solution

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Machine translation of the English, by gpt-5-6. Not checked by a person.