Bourbaki

Exercise 18, § 6

Algebra, X

Let G be a finite group and M a Z(G)\mathbf{Z}^{(G)}-module. We say that M is cohomologically trivial if for every subgroup H of G and for every q∈Zq \in \mathbf{Z}, the group H^q(H,M)\hat{H}^q(H, M) is zero. a) Now prove that a Z(G)\mathbf{Z}^{(G)}-module projective relatively to Z\mathbf{Z} (in particular an induced module, cf. exercise 12) is cohomologically trivial. b) Let n, r, k be three integers such that r divides (kn−1)(k^n - 1); let G be a cyclic group of order n, σ\sigma a generator of G. We endow the Z\mathbf{Z}-module M=Z/rZM = \mathbf{Z}/r\mathbf{Z} with the structure of Z(G)\mathbf{Z}^{(G)}-module defined by σm=km\sigma m = km for every m∈Mm \in M. Prove that M is projective relatively to Z\mathbf{Z} if and only if n and r are relatively prime. c) With the notations of b), show that for H^q(G,M)=0\hat{H}^q(G, M) = 0 for every q∈Zq \in \mathbf{Z} to hold, it is necessary and sufficient that one has (r,k−1)(r,1+k+⋯+kn−1)=r(r, k - 1)(r, 1 + k + \cdots + k^{n-1}) = r. In particular if r=kn−1r = k^n - 1, show that M is cohomologically trivial. d) Deduce from b) and c) an example of a Z(G)\mathbf{Z}^{(G)}-module that is cohomologically trivial which is not projective relatively to Z\mathbf{Z}, and of a Z(G)\mathbf{Z}^{(G)}-module M such that H^q(G,M)=0\hat{H}^q(G, M) = 0 for every q∈Zq \in \mathbf{Z} which is not cohomologically trivial. ¶19) Let p be a prime number, G a p-group, M a Z(G)\mathbf{Z}^{(G)}-module. We put A=Fp(G)A = F_p^{(G)}. a) Suppose that pM=0pM = 0. Show that the following conditions are equivalent: α) There exists a rational integer q such that H^q(G,M)=0\hat{H}^q(G, M) = 0.

EXERCISES

β) M is cohomologically trivial (exercise 18). γ) M is an induced Z(G)\mathbf{Z}^{(G)}-module. δ) The A-module M is free. (To prove that α) implies δ), reduce to the case where q=−2q = -2; show that one then has

Tor⁡1A(Fp,M)=0, \operatorname{Tor}_1^A(F_p, M) = 0,
and conclude with exercise 4, p. 185 and exercise 22 of VIII, § 8). b) Suppose that multiplication by p is injective in M. Show that the following conditions are equivalent: α) There exists an integer q such that the groups H^q(G,M)\hat{H}^q(G, M) and H^q+1(G,M)\hat{H}^{q+1}(G, M) are zero. β) M is cohomologically trivial. γ) The A-module M/pMM/pM is free. ¶ 20) Let G be a finite group, M a Z(G)\mathbf{Z}^{(G)}-module. a) Suppose that the Z-module M is free. Show that the Z(G)\mathbf{Z}^{(G)}-module M is projective if and only if for every Sylow subgroup H ⊂G\subset G, the Z(H)\mathbf{Z}^{(H)}-module M is cohomologically trivial. (To prove that the condition is sufficient, consider a resolution 0→R→L→M→00 \to R \to L \to M \to 0 of the Z(G)\mathbf{Z}^{(G)}-module M, where L is free; show that the Z(H)\mathbf{Z}^{(H)}-module Q = HomZ_\mathbf{Z}(M, N) is cohomologically trivial by observing that Q/pQ is cohomologically trivial and by using exercise 19. Deduce from exercise 17, e) that one has H1(G,Q)=0H^1(G, Q) = 0, and conclude that M is projective.) b) Show that the following conditions are equivalent: α) The Z(G)\mathbf{Z}^{(G)}-module M is cohomologically trivial. β) The Z(G)\mathbf{Z}^{(G)}-module M admits a finite projective resolution. γ) The Z(G)\mathbf{Z}^{(G)}-module M admits a projective resolution of length one. (To show that α) implies γ), consider an exact sequence 0→R→L→M→00 \to R \to L \to M \to 0, where L is a free Z(G)\mathbf{Z}^{(G)}-module, and apply a) to R.) c) Suppose that the Z-module M is divisible. Show that the Z(G)\mathbf{Z}^{(G)}-module M is cohomologically trivial if and only if it is injective (consider an exact sequence 0→M→I→Q→00 \to M \to I \to Q \to 0, where I is an injective Z(G)\mathbf{Z}^{(G)}-module, and show, using b), that the Z(G)\mathbf{Z}^{(G)}-module HomZ_\mathbf{Z}(Q, M) is cohomologically trivial). d) For a Z(G)\mathbf{Z}^{(G)}-module to be cohomologically trivial, it is necessary and sufficient that it admit an injective resolution of length 1. ¶ 21) Let G be a cyclic group of finite order. a) If M is a Z(G)\mathbf{Z}^{(G)}-module and q an even (resp. odd) rational integer, the group H^q(G,M)\hat{H}^q(G, M) is isomorphic to H^0(G,M)\hat{H}^0(G, M) (resp. H^1(G,M)\hat{H}^1(G, M)) (cf. exercise 7). b) Let C\mathscr{C} denote the set of classes of finitely generated Z(G)\mathbf{Z}^{(G)}-modules T such that the groups H^q(G,T)\hat{H}^q(G, T) are finite for every q∈Zq \in \mathbf{Z}; if the Z(G)\mathbf{Z}^{(G)}-module M is of type C\mathscr{C}, put
h(M)=Card⁡(H0(G,M))/Card⁡(H1(G,M)). h(M) = \operatorname{Card}(H^0(G, M))/\operatorname{Card}(H^1(G, M)).
Let 0→M′→M→M′′→00 \to M' \to M \to M'' \to 0 be an exact sequence of Z(G)\mathbf{Z}^{(G)}-modules. Show that if two of the modules M’, M, M” are of type C\mathscr{C}, the third is also of type C\mathscr{C}, and that one then has h(M)=h(M′) h(M′′)h(M) = h(M')\ h(M''). In particular, the function h defines a homomorphism of the grothendieck group K(C\mathscr{C}) into the multiplicative group Q∗\mathbf{Q}^*. c) Let M be a finite Z(G)\mathbf{Z}^{(G)}-module. Show that M is of type C\mathscr{C} and that one has h(M)=1h(M) = 1. d) Suppose that the order of G is a prime number p. Let C′\mathscr{C}' denote the set of classes of finitely generated Z(G)\mathbf{Z}^{(G)}-modules in which multiplication by p has a finite kernel and cokernel; if M is of type C′\mathscr{C}', put φ(M)=Card⁡(Coker⁡pM)/Card⁡(Ker⁡pM)\varphi(M) = \operatorname{Card}(\operatorname{Coker} p_M)/\operatorname{Card}(\operatorname{Ker} p_M). Prove as in b) that φ\varphi defines a homomorphism of K(C′\mathscr{C}') into Q∗\mathbf{Q}^*. e) Show that K(C′\mathscr{C}') is generated by the classes of the Z(G)\mathbf{Z}^{(G)}-modules T possessing one of the following properties: (i) T is finite. (ii) Multiplication by p in T is bijective. (iii) T=ZT = \mathbf{Z} endowed with the trivial action of G. (iv) T=Z(G)T = \mathbf{Z}^{(G)}. (v) T=Qp/ZpT = \mathbf{Q}_p/\mathbf{Z}_p (cf. TG, III, p. 84, exercise 23), endowed with the trivial action of G. (vi) T=Z(G)⊗Z(Qp/Zp)T = \mathbf{Z}^{(G)} \otimes_\mathbf{Z} (\mathbf{Q}_p/\mathbf{Z}_p). (First show that every Z(G)\mathbf{Z}^{(G)}-module of type C′\mathscr{C}' can be written in K(C′\mathscr{C}') as the sum of a Z(G)\mathbf{Z}^{(G)}-module of finite type over Z\mathbf{Z} and of a Z(G)\mathbf{Z}^{(G)}-module in which multiplication by p is surjective. Then determine the structure of the simple modules over the rings Q(G)\mathbf{Q}^{(G)} and Qp(G)\mathbf{Q}_p^{(G)}.)

g) Deduce from what precedes that one has C′⊂C\mathscr{C}' \subset \mathscr{C} and that if M is a Z(G)\mathbf{Z}^{(G)}-module of type C′\mathscr{C}', one has

h(M)p−1=(φ(H0(G,M)))p/φ(M). h(M)^{p-1} = (\varphi(H^0(G, M)))^p / \varphi(M) .
(Verify the formula in the six cases considered in f).) 22) Let K be a commutative field, L a finite galois extension of K, G its galois group. a) Prove that the exact sequence of G-modules
0→μn(L)→L∗→x↦xnL∗n→0 0 \to \mu_n(L) \to L^* \xrightarrow{x \mapsto x^n} L^{*n} \to 0
allows one to define an isomorphism kL:(Ln∩K∗)/K∗n→H1(G,μn(L))k_L : (L^n \cap K^*)/K^{*n} \to H^1(G, \mu_n(L)). When μn(K)\mu_n(K) has n elements and when one identifies H1(G,μn(L))H^1(G, \mu_n(L)) with Hom (G,μn(K))(G, \mu_n(K)), prove that kLk_L coincides with the homomorphism defined in V, § 11, No. 8. b) Let p be a prime number; suppose that K is of characteristic p. Prove that the exact sequence of G-modules (V, § 11, No. 9)
0→Fp→L→ρp(L)→0 0 \to F_p \to L \xrightarrow{\rho} p(L) \to 0
allows one to define an isomorphism aL:(p(L)∩K)/p(K)→H1(G,Fp)a_L : (p(L) \cap K)/p(K) \to H^1(G, F_p) which coincides with the homomorphism defined in loc. cit. if one identifies H1(G,Fp)H^1(G, F_p) with Hom (G,Fp)(G, F_p). 23) Let G be a group, M a group with operators in G (I, p. 29, Def. 2). We shall denote by gm^g m the composite of g∈Gg \in G and m∈Mm \in M. We shall say that M is a G-group if one has h(gm)=hgm^h(^g m) = ^{hg} m for m∈M,g,h∈Gm \in M, g, h \in G, in other words if the mapping φ\varphi from G into Aut (M) such that φ(g).m=gm\varphi(g).m = ^g m for g∈G,m∈Mg \in G, m \in M is a homomorphism. If M is a G-group, we denote by H0(G,M)H^0(G, M) the subgroup of M formed by the elements m∈Mm \in M such that gm=m^g m = m for all g∈Gg \in G, and by Z1(G,M)Z^1(G, M) the set of mappings hh from G into M such that
h(gg′)=h(g) gh(g′)forg,g′∈G. h(gg') = h(g)\ ^gh(g') \quad \text{for} \quad g, g' \in G .
a) We say that two elements h1,h2h_1, h_2 of Z1(G,M)Z^1(G, M) are cohomologous if there exists an element m of M such that h2(g)=m−1 h1(g) gmh_2(g) = m^{-1}\ h_1(g)\ ^g m for all g∈Gg \in G. Prove that the relation thus defined is an equivalence relation on Z1(G,M)Z^1(G, M); the quotient set is denoted by H1(G,M)H^1(G, M). The class in H1(G,M)H^1(G, M) of the mapping i∈Z1(G,M)i \in Z^1(G, M) such that i(g)=1Mi(g) = 1_M for all g∈Gg \in G is denoted by eG,Me_{G, M} or simply eMe_M. b) Let f:M→Nf : M \to N be a homomorphism of G-groups (I, p. 30, Def. 3); prove that ff induces a group homomorphism f0:H0(G,M)→H0(G,N)f^0 : H^0(G, M) \to H^0(G, N), and a mapping f1:H1(G,M)→H1(G,N)f^1 : H^1(G, M) \to H^1(G, N) such that f1(eM)=eNf^1(e_M) = e_N. c) Let M→iN→pQM \xrightarrow{i} N \xrightarrow{p} Q be an exact sequence of G-groups and homomorphisms, with i injective, p surjective and
Im⁡(i)=Ker⁡(p). \operatorname{Im}(i) = \operatorname{Ker}(p) .
Prove that the group N′=p−1(H0(G,Q))N' = p^{-1}(H^0(G, Q)) acts on Z1(G,M)Z^1(G, M) in such a way that (n.h)(g)=n−1 h(g) gn(n.h)(g) = n^{-1}\ h(g)\ ^gn for n∈N′,h∈Z1(G,M),g∈Gn \in N', h \in Z^1(G, M), g \in G; prove that this action defines by passing to the quotient an action of H0(G,Q)H^0(G, Q) on H1(G,M)H^1(G, M). The mapping i1:H1(G,M)→H1(G,N)i^1 : H^1(G, M) \to H^1(G, N) passes to the quotient and defines a bijection of H1(G,M)/H0(G,Q)H^1(G, M)/H^0(G, Q) onto Im⁡(i1)\operatorname{Im}(i^1). d) The action of H0(G,Q)H^0(G, Q) on H1(G,M)H^1(G, M) allows one to define a mapping ∂:H0(G,Q)→H1(G,M)\partial : H^0(G, Q) \to H^1(G, M) by ∂(q)=q.eM\partial(q) = q.e_M for q∈H0(G,Q)q \in H^0(G, Q). Prove that one has
Im⁡(i0)=Ker⁡(p0),Im⁡(p0)=∂−1(eM),Im⁡(∂)=(i1)−1(eN),Im⁡(i1)=(p1)−1(eQ). \operatorname{Im}(i^0) = \operatorname{Ker}(p^0), \operatorname{Im}(p^0) = \partial^{-1}(e_M), \quad \operatorname{Im}(\partial) = (i^1)^{-1}(e_N), \quad \operatorname{Im}(i^1) = (p^1)^{-1}(e_Q) .
e) Suppose now that i(M)i(M) is contained in the center of N. Prove that ∂\partial is a group homomorphism; construct an action of the group H1(G,M)H^1(G, M) on the set H1(G,N)H^1(G, N) such that the mapping p1p^1 passes to the quotient and defines a bijection of H1(G,N)/H1(G,M)H^1(G, N)/H^1(G, M) onto Im⁡(p1)\operatorname{Im}(p^1). f) Let E be the set of mappings kk from G into N such that p∘k∈Z1(G,Q)p \circ k \in Z^1(G, Q). For k∈Ek \in E, prove that there exists an element fkf_k of Z2(G,M)Z^2(G, M) such that i(fk(x,y))=k(x) xk(y) (k(xy))−1i(f_k(x, y)) = k(x)\ ^xk(y)\ (k(xy))^{-1} for x,y∈Gx, y \in G. Prove that the mapping k↦fkk \mapsto f_k defines by passing to the quotient a mapping ∂1:H1(G,Q)→H2(G,M)\partial^1 : H^1(G, Q) \to H^2(G, M). Prove that one has Im⁡(p1)=(∂1)−1(0)\operatorname{Im}(p^1) = (\partial^1)^{-1}(0). 24) Let K be a commutative field, L a finite galois extension of K, with galois group G. Let V (resp. V’) be a K-vector space, t (resp. t’) a tensor of type (p,q)(p, q) on V (resp. V’) (III, p. 63). We call a K-isomorphism (or simply an isomorphism) of (V,t)(V, t) onto (V′,t′)(V', t') a K-linear isomorphism u:V→V′u : V \to V' such that (Tp(u)⊗Tq(u~)) (t)=t′(\mathbf{T}^p(u) \otimes \mathbf{T}^q(\tilde{u}))\ (t) = t'. We shall denote by VLV_L the L-vector space L⊗KVL \otimes_K V and by tLt_L the tensor of type (p,q)(p, q) on VLV_L deduced from t by extension of scalars. We denote by FL/K(V,t)F_{L/K}(V, t) the set of isomorphism classes of pairs (W,τ)(W, \tau) such that (WL,τL)(W_L, \tau_L) is L-isomorphic to (VL,tL)(V_L, t_L).

EXERCISES

(a) Let M be the group of L-automorphisms of (VL,tL)(V_L, t_L). For m∈Mm \in M and σ∈G\sigma \in G, put

∘m=πV(σ)∘m∘πV(σ)−1, ^{\circ} m = \pi_V(\sigma) \circ m \circ \pi_V(\sigma)^{-1},
where πV:G→AutK(VL)\pi_V : G \to \mathrm{Aut}_K(V_L) denotes the action of G on VL=L⊗KVV_L = L \otimes_K V deduced from the action of G on L. Now prove that one thus defines a structure of G-group on M. (b) Let (W,τ)(W, \tau) be an element of FL/K(V,t)F_{L/K}(V, t), and let uu be an L-isomorphism of (VL,tL)(V_L, t_L) onto (WL,τL)(W_L, \tau_L). For σ∈G\sigma \in G, denote by fu(σ)f_u(\sigma) the element u−1∘πW(σ)∘u∘πV(σ)−1u^{-1} \circ \pi_W(\sigma) \circ u \circ \pi_V(\sigma)^{-1} of M. Now prove that fu∈Z1(G,M)f_u \in Z^1(G, M) (exercise 23), and that its class in H1(G,M)H^1(G, M) is independent of the choice of uu; denote it by θ(W,τ)\theta(W, \tau). (c) Now prove that the mapping θ:FL/K(V,t)→H1(G,M)\theta : F_{L/K}(V, t) \to H^1(G, M) is bijective, and that one has θ(V,t)=eM\theta(V, t) = e_M.

¶25) Let K be a commutative field, L a finite galois extension of K, G its galois group. We make G operate on the group GL(n,L)\mathbf{GL}(n, L) by putting σ(aij)=(σ(aij))\sigma(a_{ij}) = (\sigma(a_{ij})) for σ∈G\sigma \in G, (aij)∈GL(n,L)(a_{ij}) \in \mathbf{GL}(n, L). Every subgroup of GL(n,L)\mathbf{GL}(n, L) stable for this action is thus endowed with a structure of G-group (exercise 23). a) Now prove that the sets H1(G,GL(n,L))H^1(G, \mathbf{GL}(n, L)) and H1(G,SL(n,L))H^1(G, \mathbf{SL}(n, L)) are reduced to one element (cf. V, § 10, no 5, prop. 9). b) Now prove that the set H1(G,PGL(n,L))H^1(G, \mathbf{PGL}(n, L)) identifies with the set of isomorphism classes of central simple algebras S such that the algebra L⊗KSL \otimes_K S is isomorphic to Mn(L)M_n(L) (use exercise 24). By associating with such an algebra its class in the group Br(K, L) (VIII, § 13) and by identifying this last group with H2(G,L∗)H^2(G, L^*) (loc. cit.), one obtains a mapping H1(G,PGL(n,L))→H2(G,L∗)H^1(G, \mathbf{PGL}(n, L)) \to H^2(G, L^*) which is the opposite of the mapping ∂1\partial^1 (exercise 23, f)) deduced from the extension L∗→GL(n,L)→PGL(n,L)L^* \to \mathbf{GL}(n, L) \to \mathbf{PGL}(n, L). Now prove that the image of ∂1\partial^1 is formed by elements of order n in H2(G,L∗)H^2(G, L^*). c) Now prove that the set H1(G,Sp(2n,L))H^1(G, \mathbf{Sp}(2n, L)) is reduced to one element (cf. IX, § 5, no 1, th. 1). d) Let Q be a quadratic form on the K-vector space V, QLQ_L the quadratic form which is deduced from it on L⊗KVL \otimes_K V. Now prove that H1(G,O(QL))H^1(G, O(Q_L)) identifies with the set of isomorphism classes of quadratic forms Q’ on V such that QL′Q'_L is isomorphic to QLQ_L. 26) We denote by AeA^e the k-algebra A⊗kA0A \otimes_k A^0; every (A,A)(A, A)-bimodule is naturally endowed with a structure of left AeA^e-module and also with a structure of right AeA^e-module. Let M be an (A,A)(A, A)-bimodule, nn an integer ⩾0\geqslant 0; we put:

Hn(A,M)=TornAe(M,A)Hn(A,M)=ExtAen(A,M). H_n(A, M) = \mathrm{Tor}_n^{A^e}(M, A) \qquad H^n(A, M) = \mathrm{Ext}_{A^e}^n(A, M).
a) The k-module H0(A,M)H_0(A, M) is isomorphic to the quotient of M by the sub-k-module generated by the elements (am−ma)(am - ma) for a∈A,m∈Ma \in A, m \in M; the k-module H0(A,M)H^0(A, M) is isomorphic to the sub-k-module of M formed by the elements m such that am=maam = ma for all a∈Aa \in A. The k-module H1(A,M)H^1(A, M) identifies with the quotient of the k-module of derivations Dk(A,M)D_k(A, M) by the sub-k-module of inner derivations, that is to say derivations dmd_m, for m∈Mm \in M, defined by dm(a)=am−mad_m(a) = am - ma for all a∈Aa \in A (cf. III, p. 132). b) Under the assumption that A is a k-module projective. Now prove that the standard resolution B(A) (X, p. 58) defines a projective resolution of the left AeA^e-module A. Deduce that the k-modules Hn(A,M)H^n(A, M) are isomorphic to the homology modules of the complex C(A,M)C(A, M), where, for p⩾0p \geqslant 0, Cp(A,M)C^p(A, M) is the k-module of k-multilinear mappings from ApA^p into M, Cp(A,M)=0C^p(A, M) = 0 for p<0p < 0, the differential being given by the formula:
(df)(x0,...,xp)=x0.f(x1,...,xp)+∑i=0p−1(−1)i+1f(x0,...,xi.xi+1,...,xp) (df)(x_0, ..., x_p) = x_0 . f(x_1, ..., x_p) + \sum_{i=0}^{p-1} (-1)^{i+1} f(x_0, ..., x_i . x_{i+1}, ..., x_p)
+(−1)p+1f(x0,...,xp−1).xp + (-1)^{p+1} f(x_0, ..., x_{p-1}) . x_p
for f∈Cp(A,M)f \in C^p(A, M), x0,...,xp∈Ax_0, ..., x_p \in A. Give an analogous expression for the k-modules Hn(A,M)H_n(A, M). c) Under the assumption of b), let ρ:k→k′\rho : k \to k' be a homomorphism of commutative rings, A′A' the k′k'-algebra k′⊗kAk' \otimes_k A, M′M' an (A′,A′)(A', A')-bimodule. Now prove that the k-modules Hn(A,M′)H_n(A, M') and Hn(A′,M′)H_n(A', M') (resp. Hn(A,M′)H^n(A, M') and Hn(A′,M′)H^n(A', M')) are isomorphic. d) We now suppose that k is a field. Let B be a second k-algebra (associative and unital), M an (A,A)(A, A)-bimodule, N a (B,B)(B, B)-bimodule. For all n⩾0n \geqslant 0, define an isomorphism of k-modules
Hn(A⊗kB,M⊗kN)→⨁p+q=n(Hp(A,M)⊗kHq(B,N)). H_n(A \otimes_k B, M \otimes_k N) \to \bigoplus_{p+q=n} (H_p(A, M) \otimes_k H_q(B, N)).
If one supposes moreover that A and B are of finite dimension over k, now prove that there exists likewise a k-isomorphism
Hn(A⊗kB,M⊗kN)→⨁p+q=n(Hp(A,M)⊗kHq(B,N))for all n⩾0 H^n(A \otimes_k B, M \otimes_k N) \to \bigoplus_{p+q=n} (H^p(A, M) \otimes_k H^q(B, N)) \quad \text{for all } n \geqslant 0
(use X, p. 76, th. 3).

e) Let M, N be two left A-modules, P a right A-module, such that the k-modules Hom_k(M, N) and M ⊗k\otimes_k P have natural structures of (A, A)-bimodules. Define for every n≥0n \geq 0 isomorphisms of k-modules:

Hn(A,Homk(M,N))→ExtAn(M,N)andHn(A,M⊗kP)→TornA(P,M). H^n(A, \mathrm{Hom}_k(M, N)) \to \mathrm{Ext}_A^n(M, N) \quad \text{and} \quad H_n(A, M \otimes_k P) \to \mathrm{Tor}_n^A(P, M).

**T 27) An augmentation of the k-algebra A is called a unital homomorphism of k-algebras π:A→k\pi : A \to k; the pair (A, π\pi) is called an augmented k-algebra. The augmentation endows k with a structure of left A-module. Let M be a left A-module, N a right A-module; we set

Hn(A,π;N)=TornA(N,k)andHn(A,π;M)=ExtAn(k,M)for all n≥0. H_n(A, \pi ; N) = \mathrm{Tor}_n^A(N, k) \quad \text{and} \quad H^n(A, \pi ; M) = \mathrm{Ext}_A^n(k, M) \quad \text{for all } n \geq 0.

a) We denote by M(π)M_{(\pi)} (resp. N(π)N_{(\pi)}) the group M (resp. N) endowed with the structure of (A, A)-bimodule defined by:

ama′=π(a′)am(resp. ana′=nπ(a)a′fora, a′∈A, m∈M, n∈N. ama' = \pi(a') am \quad (\text{resp. } ana' = n\pi(a) a' \quad \text{for} \quad a,\ a' \in A,\ m \in M,\ n \in N.

Prove that the k-module H0(A,π;N)H_0(A, \pi ; N) (resp. H0(A,π;M)H^0(A, \pi ; M), resp. H1(A,π;M)H^1(A, \pi ; M)) is isomorphic to the k-module H0(A,N(π))H_0(A, N_{(\pi)}) (resp. H0(A,M(π))H^0(A, M_{(\pi)}), resp. H1(A,M(π))H^1(A, M_{(\pi)})) defined in exercise 26.

b) We now suppose that A is a projective k-module. Define, using the standard resolution (X, p. 58), k-isomorphisms φn:Hn(A,N(π))→Hn(A,π;N)\varphi_n : H_n(A, N_{(\pi)}) \to H_n(A, \pi ; N) and φn:Hn(A,M(π))→Hn(A,π;M)\varphi^n : H^n(A, M_{(\pi)}) \to H^n(A, \pi ; M) for all n≥0n \geq 0.

c) Suppose that there exists a homomorphism of k-algebras ρ:A→Ae\rho : A \to A^e which makes AeA^e a projective right A-module and such that the left ideal of AeA^e generated by ρ(Ker π)\rho(\mathrm{Ker}\ \pi) is the kernel of the homomorphism A⊗kAe→AA \otimes_k A^e \to A defined by multiplication in A. Prove that there exist, for every (A, A)-bimodule Q and every integer n≥0n \geq 0, k-isomorphisms Hn(A,π;Q)→Hn(A,Q)H_n(A, \pi ; Q) \to H_n(A, Q) (resp. Hn(A,π;Q)→Hn(A,Q)H^n(A, \pi ; Q) \to H^n(A, Q)), Q being considered as a right A-module (resp. left A-module) via the homomorphism ρ\rho. (Use the canonical homomorphisms of X, p. 109.)

d) Prove that the hypotheses of c) are verified in the following cases: α) A is the algebra (over k) of a group G, ρ\rho is defined by ρ(eg)=eg⊗eg−1\rho(e_g) = e_g \otimes e_{g^{-1}}. β) A is the tensor algebra (resp. symmetric algebra) of a projective k-module V; ρ\rho is defined by

ρ(v)=v⊗1−1⊗v. \rho(v) = v \otimes 1 - 1 \otimes v.

\* γ) A is the enveloping algebra of a Lie algebra g over k, free as a k-module; one has

ρ(x)=x⊗1−1⊗xforx∈g \rho(x) = x \otimes 1 - 1 \otimes x \quad \text{for} \quad x \in g

(use cor. 5 to th. 1 of LIE I, § 2, no 7).

δ) A is the ring of functions of a smooth algebraic group G over a field k; one takes

ρ(f)=∑i=1kfi′⊗fi′′,wheref(gh−1)=∑i=1kfi′(g) fi′′(h)forg, h∈G. ∗ \rho(f) = \sum_{i=1}^k f_i' \otimes f_i'', \quad \text{where} \quad f(gh^{-1}) = \sum_{i=1}^k f_i'(g)\ f_i''(h) \quad \text{for} \quad g,\ h \in G.\ *

\* 28) Let g be a Lie algebra over the commutative ring k, U its enveloping algebra. We endow k with the structure of left U-module corresponding to the trivial representation of g. Let N be a right g-module, M a left g-module, n an integer ≥0\geq 0; we set

Hn(g,N)=TornU(N,k)andHn(g,M)=ExtUn(k,M). H_n(g, N) = \mathrm{Tor}_n^U(N, k) \quad \text{and} \quad H^n(g, M) = \mathrm{Ext}_U^n(k, M).

a) The k-module H0(g,N)H_0(g, N) (resp. H0(g,M)H^0(g, M)) is isomorphic to N/NgN/Ng (resp. to the submodule of M formed by the elements annihilated by g). We denote by Z1(g,M)Z^1(g, M) (resp. B1(g,M)B^1(g, M)) the sub-k-module of Homk(g,M)\mathrm{Hom}_k(g, M) formed by the elements f such that f([x,y])=xf(y)−yf(x)f([x, y]) = xf(y) - yf(x) for x,y∈gx, y \in g (resp. by the elements fmf_m, for m∈Mm \in M, such that fm(x)=xmf_m(x) = xm for x∈gx \in g). Prove that H1(g,M)H^1(g, M) is identified with the quotient Z1(g,M)/B1(g,M)Z^1(g, M)/B^1(g, M).

b) We now suppose that g is a free k-module. Prove that the k-modules Hn(g,M)H^n(g, M) are identified with the homology modules of the complex C(g,M)C(g, M), where for p≥0p \geq 0, Cp(g,M)C^p(g, M) is the k-module of alternating multilinear mappings from gpg^p into M, Cp(g,M)=0C^p(g, M) = 0 for p<0p < 0, the differential being given by the formula

df(x1,...,xp+1)=∑1≤i≤p+1(−1)i+1xi.f(x1,...,x^i,...,xp+1) df(x_1, ..., x_{p+1}) = \sum_{1 \leq i \leq p+1} (-1)^{i+1} x_i . f(x_1, ..., \hat{x}_i, ..., x_{p+1})
+∑1≤i<j≤p+1(−1)i+jf([xi,xj],x1,...,x^i,...,x^j,...,xp+1) + \sum_{1 \leq i < j \leq p+1} (-1)^{i+j} f([x_i, x_j], x_1, ..., \hat{x}_i, ..., \hat{x}_j, ..., x_{p+1})

for f∈Cp(g,M)f \in C^p(g, M), x1,...,xp+1∈gx_1, ..., x_{p+1} \in g (where the sign ^\hat{} on a letter means that it is to be omitted).

Give an analogous expression for the kk-modules Hp(g,M)H_p(\mathfrak{g},M). (Use X, p. 184, exercise 21.)

c) Suppose that dim⁡k(g)=n<∞\dim_k(\mathfrak{g})=n<\infty. Now prove that Hp(g,M)=0H^p(\mathfrak{g},M)=0 for all p>n+1p>n+1 and all g\mathfrak{g}-modules MM, and that there exists a g\mathfrak{g}-module NN such that Hn(g,N)≠0H^n(\mathfrak{g},N)\neq0 (take N=ΛngN=\Lambda^n\mathfrak{g}, where g\mathfrak{g} operates by the formula

x.(x1∧⋯∧xn)=∑i=1nx1∧⋯∧xi−1∧[x,xi]∧xi+1∧⋯∧xn; x.(x_1\wedge\cdots\wedge x_n)=\sum_{i=1}^{n}x_1\wedge\cdots\wedge x_{i-1}\wedge[x,x_i]\wedge x_{i+1}\wedge\cdots\wedge x_n;

now prove that df=0df=0 for all f∈Cn−1(g,N)f\in C^{n-1}(\mathfrak{g},N).

d) The adjoint representation of g\mathfrak{g} and the representation of g\mathfrak{g} on MM define a representation θ\theta of g\mathfrak{g} in C(g,M)C(\mathfrak{g},M), such that

(θ(x)f)(x1,…,xp)=x.f(x1,…,xp)−∑i=1pf(x1,…,[x,xi],…,xp) (\theta(x)f)(x_1,\ldots,x_p)=x.f(x_1,\ldots,x_p)-\sum_{i=1}^{p}f(x_1,\ldots,[x,x_i],\ldots,x_p)

for f∈Cp(g,M)f\in C^p(\mathfrak{g},M), x,x1,…,xp∈gx,x_1,\ldots,x_p\in\mathfrak{g}. Show that, for all x∈gx\in\mathfrak{g}, θ(x)\theta(x) is an endomorphism homotopic to zero of the complex C(g,M)C(\mathfrak{g},M) (define a homotopy i(x)i(x) by putting (i(x)f)(x1,…,xp)=f(x,x1,…,xp)(i(x)f)(x_1,\ldots,x_p)=f(x,x_1,\ldots,x_p)). \* 29) We retain the notations of the preceding exercise; suppose in addition that kk is a field of characteristic zero, and that the Lie algebra g\mathfrak{g} is semisimple (LIE, I, § 6). Let MM be a g\mathfrak{g}-module of finite dimension over kk.

a) If MM is simple and nontrivial, one has Hp(g,M)=0H^p(\mathfrak{g},M)=0 for all p>0p>0 (the bilinear form on g\mathfrak{g} associated with MM is non-degenerate (LIE, I, § 6, No. 1, prop. 1); observe that multiplication by the corresponding Casimir element (LIE, I, § 3, No. 7) is zero in kk and bijective in MM).

b) Now prove that H1(g,M)=0H^1(\mathfrak{g},M)=0 whatever MM may be (use a) and the fact that g=g\mathfrak{g}=\mathfrak{g}). Conversely, a kk-Lie algebra h\mathfrak{h} (of finite dimension) such that H1(h,M)=0H^1(\mathfrak{h},M)=0 for every h\mathfrak{h}-module MM of finite dimension is semisimple.

c) Equip kk with the structure of g\mathfrak{g}-module corresponding to the trivial representation. Now prove that, for all p>0p>0, the kk-vector space Hp(g,k)H^p(\mathfrak{g},k) is isomorphic to the vector subspace of Cp(g,k)C^p(\mathfrak{g},k) formed by the alternating pp-linear forms ff which are invariant, that is to say such that

∑i=1pf(x1,…,[x,xi],…,xp)=0for all x,x1,…,xp∈g. \sum_{i=1}^{p}f(x_1,\ldots,[x,x_i],\ldots,x_p)=0\quad\text{for all }x,x_1,\ldots,x_p\in\mathfrak{g}.

(Deduce from the semisimplicity of the representations of g\mathfrak{g} and from exercise 28, d) that Hp(g,k)H^p(\mathfrak{g},k) is isomorphic to Hp(Cg(g),k)H^p(C_{\mathfrak{g}}(\mathfrak{g}),k), where Cg(g)C_{\mathfrak{g}}(\mathfrak{g}) is the subcomplex of C(g,k)C(\mathfrak{g},k) annihilated by all the endomorphisms θ(x)\theta(x) for x∈gx\in\mathfrak{g}; then now prove that Cg(g)C_{\mathfrak{g}}(\mathfrak{g}) has zero differential.)

d) Deduce from c) that H2(g,M)=0H^2(\mathfrak{g},M)=0 for every g\mathfrak{g}-module MM of finite dimension over kk. (Show that every invariant bilinear form on g\mathfrak{g} is symmetric, by reducing to the case where g\mathfrak{g} is simple and kk algebraically closed.) \*

Solution

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Machine translation of the English, by gpt-5-mini, gpt-5-6, gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.