Bourbaki

Exercise 1, § 7

Algebra, X, p. 197

Let kk be a commutative ring, AA a kk-algebra associative and unital, MM an (A,A)(A,A)-bimodule. We call extension of AA by MM the data of a kk-algebra BB associative and unital and of an exact sequence of kk-modules

(E):0⟶M→iB→pA⟶0, (\mathscr{E}):\quad 0\longrightarrow M \xrightarrow{i} B \xrightarrow{p} A\longrightarrow0,

where pp is an homomorphism of algebras and where

i(p(b)m)=bi(m)andi(mp(b))=i(m)bfor b∈B, m∈M. i(p(b)m)=bi(m)\quad\text{and}\quad i(mp(b))=i(m)b\quad\text{for }b\in B,\ m\in M.

Two extensions 0⟶M→iB→pA⟶00\longrightarrow M\xrightarrow{i}B\xrightarrow{p}A\longrightarrow0 and 0⟶M→i′B′→p′A⟶00\longrightarrow M\xrightarrow{i'}B'\xrightarrow{p'}A\longrightarrow0 are said to be equivalent if there exists an homomorphism of algebras u:B⟶B′u:B\longrightarrow B' such that p′∘u=pp'\circ u=p and u∘i=i′u\circ i=i'; the homomorphism uu is then bijective.

(a) Suppose that the exact sequence of kk-modules 0⟶M→iB→pA⟶00\longrightarrow M\xrightarrow{i}B\xrightarrow{p}A\longrightarrow0 is split; let s:A⟶Bs:A\longrightarrow B be a kk-linear section of pp. Now prove that there exists an element f∈C2(A,M)f\in C^2(A,M) (X, p. 195, exercise 26, b)) such that

s(a)s(a′)−s(aa′)=i(f(a,a′)) s(a)s(a')-s(aa')=i(f(a,a'))

for a,a′∈Aa,a'\in A. Now prove that ff is a 22-cocycle and that its class in H2(A,M)H^2(A,M) is independent of the choice of ss; we denote it by (E)(\mathscr{E}).

(b) Let Exk(A,M)Ex_k(A,M) be the set of equivalence classes of extensions of AA by MM which are trivial as extensions of kk-modules. Now prove that cc defines a bijection from Exk(A,M)Ex_k(A,M) onto H2(A,M)H^2(A,M).

c) Let E:0→M→iB→pA→0\mathscr{E}:0\to M \xrightarrow{i} B \xrightarrow{p} A\to0 and E′:0→M→i′B′→p′A→0\mathscr{E}':0\to M \xrightarrow{i'} B' \xrightarrow{p'} A\to0 be two extensions of AA by MM. Let CC denote the subalgebra of B×B′B\times B' formed by the elements (b,b′)(b,b') such that p(b)=p′(b′)p(b)=p'(b'), cc the ideal of CC formed by the elements (i(m),−i′(m))(i(m),-i'(m)) for m∈Mm\in M, B‾\overline{B} the algebra C/cC/c, π:C→B‾\pi:C\to\overline{B} the homomorphism of passing to the quotient. Let i′′:M→B‾i'':M\to\overline{B} and p′′:B‾→Ap'':\overline{B}\to A be the homomorphisms such that i′′(m)=π((m,0))i''(m)=\pi((m,0)) for m∈Mm\in M and p′′π((b,b′))=p(b)p''\pi((b,b'))=p(b) for b∈B,b′∈B′b\in B,b'\in B'. Prove that the sequence 0→M→B‾→A→00\to M\to\overline{B}\to A\to0 is an extension of AA by MM, called the sum extension of (E)(\mathscr{E}) and (E′)(\mathscr{E}'), and that one defines in this way a commutative group law on the set of equivalence classes of extensions of AA by MM. In particular, the set Exk(A,M)Ex_k(A,M) is endowed in this way with a group structure, and the mapping cc is a group isomorphism.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.