Bourbaki

Exercise 10, § 7

Algebra, X, p. 201

Let BB be a k-bigebra (III, p. 148), which is considered as an augmented k-algebra (X, p. 196, exercise 27) by the counit β:B→k\beta : B \to k; suppose that the k-module B is projective.

(a) Let M, N be two left B-modules. The homomorphism ∨\vee of exercise 7 identifies with a graded homomorphism of degree zero

H′(B,γ;M)⊗kH′(B,γ;N)→H′(B⊗kB,γ⊗γ;M⊗kN); H'(B, \gamma; M) \otimes_k H'(B, \gamma; N) \to H'(B \otimes_k B, \gamma \otimes \gamma; M \otimes_k N);

by composition with the homomorphism deduced from the comultiplication, deduce a graded homomorphism of degree zero ∪:H′(B,γ;M)⊗kH′(B,γ;N)→H′(B,γ;M⊗kN)\cup : H'(B, \gamma; M) \otimes_k H'(B, \gamma; N) \to H'(B, \gamma; M \otimes_k N).

(b) Let C be an associative and unital k-algebra, which is provided with the structure of B-module deduced from γ\gamma. Prove that the homomorphism ∪\cup defines on H′(B,γ;C)H'(B, \gamma; C) a structure of associative and unital graded k-algebra; if C is commutative and if the bigebra B is cocommutative, the algebra H′(B,γ;C)H'(B, \gamma; C) is anticommutative.

(c) Take C=kC = k. Prove that the product ∪\cup coincides with the composition product on ExtB(k,k)\mathrm{Ext}_B(k, k).

(d) Let G be a group, M and N two Z(G)\mathbf{Z}^{(G)}-modules. We provide M⊗ZNM \otimes_Z N with the structure of Z(G)\mathbf{Z}^{(G)}-module defined by g(x⊗y)=gx⊗gyg(x \otimes y) = gx \otimes gy for g∈G,x∈M,y∈Ng \in G, x \in M, y \in N. Prove that the mapping

∪:H′(G,M)⊗ZH′(G,N)→H′(G,M⊗ZN) \cup : H'(G, M) \otimes_Z H'(G, N) \to H'(G, M \otimes_Z N)

is the homomorphism induced on homology by the graded homomorphism of degree zero

u:C′(G,M)⊗ZC′(G,N)→C′(G,M⊗ZN) u : C'(G, M) \otimes_Z C'(G, N) \to C'(G, M \otimes_Z N)

defined by u(f⊗h)(g1,...,gp+q)=f(g1,...,gp)⊗g1,...,gph(gp+1,...,gp+q)u(f \otimes h)(g_1, ..., g_{p+q}) = f(g_1, ..., g_p) \otimes g_1, ..., g_p h(g_{p+1}, ..., g_{p+q}) for

f∈Cp(G,M),h∈Cq(G,N),g1...gp+q∈G. f \in C^p(G, M), \quad h \in C^q(G, N), \quad g_1 ... g_{p+q} \in G.

(Use exercise 5, p. 185.)

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.