Bourbaki

Exercise 2, § 7

Algebra, X, p. 198

We suppose that the kk-algebra AA admits an augmentation π:A→k\pi:A\to k (X, p. 196, exercise 27) and that, moreover, AA is a projective kk-module. We denote by II the kernel of π\pi. Let MM be a left AA-module.

a) Let (E):0→M(π)→B→pA→0(\mathscr{E}):0\to M_{(\pi)}\to B\xrightarrow{p}A\to0 be an extension of AA by the (A,A)(A,A)-bimodule M(π)M_{(\pi)} (X, p. 196, exercise 27); we denote by B‾\overline{B} the ideal of BB formed by the elements b∈Bb\in B such that p(b)∈Ip(b)\in I. We have i(m)b=0i(m)b=0 for m∈Mm\in M and b∈B‾b\in\overline{B}, so that B‾\overline{B} is endowed with a left AA-module structure such that p(β)b=βbp(\beta)b=\beta b for β∈B\beta\in B, b∈B‾b\in\overline{B}. Show that there exists an exact sequence of AA-modules

0→M→B‾→I→0;0\to M\to\overline{B}\to I\to0;
we denote by δ(E)\delta(\mathscr{E}) the class of this exact sequence in ExtA1(I,M)Ext^1_A(I,M).

b) Show that δ\delta defines a mapping from Exk(A,M(π))Ex_k(A,M_{(\pi)}) into ExtA1(I,M)Ext^1_A(I,M). Prove the commutativity of the diagram:

Exk(A,M(π))→δExtA1(I,M)↓c↓−δH2(A,M(π))→φExtA2(k,M) \begin{array}{ccc} Ex_k(A,M_{(\pi)})&\xrightarrow{\delta}&Ext^1_A(I,M)\\ \downarrow c&&\downarrow-\delta\\ H^2(A,M_{(\pi)})&\xrightarrow{\varphi}&Ext^2_A(k,M) \end{array}

where δ\delta is the connecting homomorphism deduced from the exact sequence 0→I→A→πk→00\to I\to A\xrightarrow{\pi}k\to0, and where φ\varphi is the isomorphism obtained by calculating with the standard resolution (X, p. 196, exercise 27, b)). Deduce that δ\delta is a group isomorphism.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.