Bourbaki

Exercise 5, § 7

Algebra, X, p. 199

Bourbaki marks this one as harder than the rest.

Let GG, FF be two groups. a) For any extension E:F→E→G\mathscr{E} : F \to E \to G of G by F (I, p. 62), the operation of E on F by inner automorphisms defines a homomorphism E→Aut(F)E \to \mathrm{Aut}(F), whence by passing to the quotient a group homomorphism θ:G→Aut(F)/Int(F)\theta : G \to \mathrm{Aut}(F)/\mathrm{Int}(F), called the homomorphism associated with the extension E\mathscr{E}. Two isomorphic extensions of G by F have the same associated homomorphism. b) Conversely, consider a group homomorphism θ:G→Aut(F)/Int(F)\theta : G \to \mathrm{Aut}(F)/\mathrm{Int}(F). Let

p:Aut(F)→Aut(F)/Int(F) p : \mathrm{Aut}(F) \to \mathrm{Aut}(F)/\mathrm{Int}(F)
be the mapping of passing to the quotient. Choose a mapping σ\sigma of G into Aut(F)\mathrm{Aut}(F) such that p∘σ=θp \circ \sigma = \theta, and a mapping ff of G×GG \times G into F such that σ(x)σ(y)(σ(xy))−1=Int(f(x,y))\sigma(x) \sigma(y) (\sigma(xy))^{-1} = \mathrm{Int}(f(x, y)) for x,y∈Gx, y \in G; put c(x,y,z)=σ(x)(f(y,z)).f(x,yz).(f(xy,z))−1.(f(x,y))−1c(x, y, z) = \sigma(x)(f(y, z)).f(x, yz).(f(xy, z))^{-1}.(f(x, y))^{-1}. Now prove that c(x,y,z)c(x, y, z) belongs to the center Z of F. c) Consider Z as a G-module by putting g.z=σ(g)(z)g.z = \sigma(g)(z) for g∈G,z∈Zg \in G, z \in Z; this definition is independent of the choice of σ\sigma. The mapping c defines an element of C3(G,Z)C^3(G, Z); now prove that c is a 3-cocycle, and that its class in H3(G,Z)H^3(G, Z) is independent of the choices of σ\sigma and ff. We denote it by ω(G,F,θ)\omega(G, F, \theta). d) Now prove that the nullity of ω(G,F,θ)\omega(G, F, \theta) is a necessary and sufficient condition for there to exist an extension of G by F having θ\theta as associated homomorphism (if ω(G,F,θ)=0\omega(G, F, \theta) = 0, show that one can choose ff in such a way that the cocycle c is zero, then define a group law on G×FG \times F). e) Suppose that ω(G,F,θ)=0\omega(G, F, \theta) = 0. Now prove that the set of isomorphism classes of extensions of G by F, with associated homomorphism θ\theta, is a principal homogeneous set under the group H2(G,Z)H^2(G, Z). f) Let H be a group, M a Z(H)\mathbf{Z}^{(H)}-module, x an element of H3(H,M)H^3(H, M). Now prove that there exists a group E with center M and a homomorphism φ:H→Aut(E)/Int(E)\varphi : H \to \mathrm{Aut}(E)/\mathrm{Int}(E), inducing on M the given H-module structure, such that ω(H,E,φ)=x\omega(H, E, \varphi) = x (take E=M×LE = M \times L, where L is the free group constructed on H×HH \times H).

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.