Bourbaki

Exercise 14, § 8

Algebra, X, p. 203

Let x be an element of A cancellable on the left. a) Show that the ideal xAxA is two-sided if and only if there exists an endomorphism σ\sigma of the ring A such that ax=xσ(a)ax = x\sigma(a) for all a∈Aa \in A. b) We suppose from now on that the conditions of a) are verified. Let M be an A-module such that xM=0xM = 0. Prove the equality dpA(M)=dpA/xA(M)+1\mathrm{dp}_A(M) = \mathrm{dp}_{A/xA}(M) + 1 (one may use the spectral sequence of exercise 6, d), p. 188). c) We suppose that x belongs to the radical of A, and that A is Noetherian. Let N be a finitely generated A-module, such that the homothety of ratio x is injective in N. Show that one has dpA(N)=dpA/Ax(N/xN)\mathrm{dp}_A(N) = \mathrm{dp}_{A/Ax}(N/xN). d) Under the conditions of c), show that one has dh(A)=dh(A/Ax)+1\mathrm{dh}(A) = \mathrm{dh}(A/Ax) + 1.

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.