Bourbaki

Exercise 20, § 8

Algebra, X, p. 204

Bourbaki marks this one as harder than the rest.

Let RR be a principal ideal domain, KK its field of fractions. We denote by BB the subring of M2(K)\mathbf{M}_2(K) formed by the matrices (a0xy)\begin{pmatrix} a & 0 \\ x & y \end{pmatrix} with a∈Ra \in R, x,y∈Kx, y \in K.

a) Now prove that BB is left noetherian but not right noetherian.

b) Now prove that dh(B)=1\mathrm{dh}(B) = 1 and dh(B∘)=2\mathrm{dh}(B^\circ) = 2.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.