Algebra, X, p. 204
Show that the following conditions are equivalent:
α) Every A-module of finite presentation and of finite projective dimension is projective.
β) Every injective A-homomorphism Ap→Aq admits a retraction.
γ) For every right ideal of finite type a distinct from A, there exists a nonzero element x of A such that xa=0.
δ) Every simple right A-module of finite presentation is isomorphic to a (minimal) right ideal of A. (Observe that condition γ) is equivalent to condition β) in the case p=1.)
T 23) Show that the following conditions are equivalent: α) Every A-module of finite projective dimension is projective. β) The ring A satisfies the equivalent conditions of exercise 21, and for every right ideal of finite type a distinct from A, there exists a nonzero element x=0 of A such that xa=0. γ) The ring A satisfies the equivalent conditions of exercise 21, and every simple A-module is a quotient of an injective A-module. (Show that α) implies that every decreasing sequence of monogenic right ideals of A is stationary by adapting the proof of exercise 21. Deduce then from exercise 22 the equivalence of α) and β). To see that α) implies γ), consider a projective covering P of the simple module M, an injective module I containing P and a projective covering Q of I; define an A-homomorphism of Q into P, and deduce from it a surjection of I onto M. To show that γ) implies α), show that an A-module M such that dpA(M)≤1 is projective by considering a projective covering p:P→M and a surjection of kerp onto a simple module.)
24) We denote by dhf (A) (resp. dif (A), resp. tdf (A)) the supremum of the projective (resp. injective, resp. flat) dimensions of the A-modules for which this dimension is finite. If A is of finite homological dimension, one has dhf(A) = dif(A) = dh(A) and tdf(A) = td(A). If td(A) < ∞, one has tdf(A) = td(A). a) Show that one has tdf (A) ≤ dif (A°) ; there is equality if A is left noetherian (use X, p. 189, exercise 3). b) Suppose A is left noetherian. Show that one has dhf(A) ≤ di_A(A_s). If di_A(A_s) and dif(A) are finite, show that they are equal (use exercise 2, p. 202). c) Let G be a finite group not reduced to the identity element, and A the ring Z(G). Show that one has
dh(A)=+∞,dhf(A)=dif(A)=tdf(A)=1,diA(As)=+∞ (cf. exercise 20, p. 193). d) Suppose the ring A autoinjective (cf. X, p. 171, exercise 26), non-semisimple. Show that every nonprojective A-module is of infinite projective dimension and infinite injective dimension. Deduce that one has
dh(A)=+∞,dhf(A)=dif(A)=tdf(A)=diA(As)=0.
25) We denote by Ae the k-algebra A⊗kA∗, and we consider A as a left Ae-module. We put
dak(A)=dpAe(A). If n is an integer
≥0, the inequality
dak(A)≤n is therefore equivalent to the vanishing of
Hn+1(A,M) for every (A, A)-bimodule M (X, p. 195, exercise 26). One has
dak(A)=dak(Ao). a) Show that one has
dak(Mn(k))=0 and
dak(k[X1,...,Xn])=n for every
n≥0. b) If k is a field, one has
dak(A)=0 if and only if the k-algebra A is absolutely semisimple (cf. VIII, § 11, no 3, th. 2). c) Let M be a free k-module. Prove that one has
dak(Tk(M))=1 (if
(ei)i∈I is a basis of M, prove that the elements
(ei⊗1−1⊗ei) form a basis of the left ideal of
Ae which is the kernel of the multiplication
A⊗kA→A, with
A=Tk(M)). d) Suppose now that the k-module A is projective. Let
ρ:k→k′ be a homomorphism of commutative rings; show that one has
dak(A⊗kk′)≤dak(A). If
ρ is injective and if
ρ(k) is a direct factor of the k-module
k′, one has equality (use X, p. 195, exercise 26, c)). e) Let B be a second k-algebra (associative and unital), projective over k. Show that
dak(A⊗kB)≤dak(A)+dak(B). If moreover k is a field and A and B are finite-dimensional over k, there is equality (use X, p. 195, exercise 26, d)). f) Suppose that k is a field. Prove the inequalities
dh(A)≤dak(A) and
dh(A∗)≤dak(A) (cf. X, p. 196, exercise 26, e)).
26) Let A be an augmented k-algebra (X, p. 196, exercise 27); suppose that there exists a homomorphism ρ:A→Ae which satisfies the conditions of X, p. 196, exercise 27, c). Show that dak(A)=dpA(k); if moreover k is a field, one has dak(A)=dpA(k)=dh(A)=dh(A∗). (Use exercise 27, b) and c), p. 196, and exercise 26, e), p. 196.) In particular, if V is a nonzero k-vector space, one has dh Tk(V)=1.
\* 27) Suppose that k is a field. Let g be a Lie algebra over k, of dimension n, and U its enveloping algebra. Show that dhU=n. (Use exercise 26, exercise 27, d), p. 196, and exercise 28, c), p. 197.) \*
**28) Let G be a group. The cohomological dimension of G, denoted by dc(G), is called the projective dimension of the Z(G)-module Z. If n is an integer, one therefore has dc(G)≤n if and only if Hq(G,M)=0 for every Z(G)-module M and every q>n.
a) Prove that one has daZ(Z(G))=dc(G) (use Exercise 26 and Exercise 27, d), p. 196).
b) If G is a free group not reduced to the identity element, one has dc(G)=1.
c) Let H be a subgroup of G; prove the inequality dc(H)≤dc(G). If dc(G)<∞ and if H is of finite index in G, show that dc(H)=dc(G) (show that for q=dc(G), the homomorphism
tq:Hq(H,M)→Hq(G,M)
of Exercise 14, p. 191, is surjective).
d) Show that the cohomological dimension of a finite group not reduced to the identity element is infinite. Deduce that if dc(G)<∞, every element of G distinct from the identity element is of infinite order (one then says that G is torsion-free).
e) If G is torsion-free and if H is a subgroup of finite index of G, show that one has dc(H)=dc(G). (If (P,p) is a projective resolution of the Z(H)-module Z and if (G:H)=n, define on the graded Z(H)-module TZn(P) a structure of Z(G)-complex in such a way that (TZn(P),p⊗n) is a projective resolution of the Z(G)-module Z.)
f) If H is a normal subgroup of G, show that one has
dc(G)≤dc(H)+dc(G/H).