Bourbaki

Exercise 13, § 2

Topological Vector Spaces, I, p. 27

Bourbaki marks this one as harder than the rest.

\* We keep the general hypotheses and the notations of Exerc. 12.

a) Let LL be a free a-module submodule of EE of dimension n=dim⁡En = \dim E. For every x∈E−{0}x \in E - \{0\}, the set of a∈Aa \in A such that ax∈Lax \in L is a fractional ideal of KK of the form mhm^h (hh a positive or negative integer); if one sets α(x)=qh\alpha(x) = q^h, and α(0)=0\alpha(0) = 0, now prove that α\alpha is an ultranorm on EE, said to be associated with the free a-module LL.

b) Conversely, if α\alpha is an ultranorm on EE, the set LαL_\alpha of the x∈Ex \in E such that α(x)≤1\alpha(x) \leq 1 is a free a-module of dimension nn. If [α][\alpha] is the norm associated with LαL_\alpha, one has α≤[α]≤qα\alpha \leq [\alpha] \leq q \alpha, and [α][\alpha] is the greatest lower bound of the norms associated with free a-modules and which are ≥α\geq \alpha. One has [qα]=q.[α][q \alpha] = q.[\alpha], and α(x)=inf⁡(q−t[qtα](x))\alpha(x) = \inf(q^{-t}[q^t \alpha](x)) for all x∈Ex \in E, where tt varies in the interval [0,1][0, 1]. Moreover, the function t↦[qtα](x)t \mapsto [q^t \alpha](x) is left continuous in this interval.

c) With the same notations, now prove that for 0≤t≤10 \leq t \leq 1, there are at most nn distinct ultranorms among the [qtα][q^t \alpha]. Conversely, let LL be the set of ultranorms associated with free a-modules of dimension nn, and let (αt)0≤t≤1(\alpha_t)_{0 \leq t \leq 1} be a growing family of ultranorms of LL such that α1=qα0\alpha_1 = q \alpha_0. Now prove that there exists a basis of EE with respect to which all the αt\alpha_t have the standard form (if u∈Au \in A is an element of valuation 1, and LtL_t the free a-module of the x∈Ex \in E such that αt(x)≤1\alpha_t(x) \leq 1, consider the vector spaces Lt/uL0L_t/uL_0 over kk). Deduce that if, moreover, for every x∈Ex \in E, t↦αt(x)t \mapsto \alpha_t(x) is left continuous in [0,1][0, 1], then there exists one and only one ultranorm α\alpha such that αt=[qtα]\alpha_t = [q^t \alpha] for all t∈[0,1]t \in [0, 1].

d) The linear group GL(E)GL(E) operates continuously in N0(E)\mathfrak{N}_0(E); now prove that it operates properly. For every α∈N0(E)\alpha \in \mathfrak{N}_0(E), the stabilizer SαS_\alpha of α\alpha in GL(E)GL(E) is the intersection of the stabilizers of the [qtα][q^t \alpha] for 0≤t≤10 \leq t \leq 1; deduce that SαS_\alpha is an open and compact subgroup of GL(E)GL(E), and consequently that the orbit of every α∈N0(E)\alpha \in \mathfrak{N}_0(E) is a closed discrete subspace of N0(E)\mathfrak{N}_0(E).

e) For every ultranorm α∈N0(E)\alpha \in \mathfrak{N}_0(E), consider the decreasing sequence of the dimensions of the kk-vector spaces Lt/uL0L_t/uL_0, where LtL_t is the A-module of the x∈Ex \in E such that [qtα](x)≤1[q^t \alpha](x) \leq 1, and tt varies from 0 to 1; this sequence is called the sequence of invariants of α\alpha. For α\alpha and β\beta to belong to the same orbit in N0(E)\mathfrak{N}_0(E), it is necessary and sufficient that Xα=XβX_\alpha = X_\beta (Exercise 12, e)) and that the sequences of invariants of α\alpha and β\beta be the same (use Exercise 12, b)).

f) Deduce from e) that the space of orbits N0(E)/GL(E)\mathfrak{N}_0(E)/GL(E) is isomorphic to the space of orbits Tn/SnT^n/\mathscr{S}_n, where the symmetric group operates on the right on TnT^n by (z1,…,zn)↦(zσ(1),…,zσ(n))(z_1, \ldots, z_n) \mapsto (z_{\sigma(1)}, \ldots, z_{\sigma(n)}). \*

1 For Exercises 12 and 13, see O. Goldman and N. Iwahori, The space of pp-adic norms, Acta math., t. CIX (1963), pp. 137-177.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.