Bourbaki

Exercise 5, § 3

Topological Vector Spaces, IV, p. 58

Bourbaki marks this one as harder than the rest.

For every integer n>0n > 0, let a(n)a^{(n)} be the double sequence (apq(n))(a^{(n)}_{pq}) (p∈N,q∈Np \in \mathbf{N}, q \in \mathbf{N}) such that apq(n)=qa^{(n)}_{pq} = q if p≤np \leq n and apq(n)=1a^{(n)}_{pq} = 1 if p>np > n. Let E be the vector space of the double sequences x=(xpq)(p,q)∈N×Nx = (x_{pq})_{(p,q) \in \mathbf{N} \times \mathbf{N}} of real numbers such that, for every integer n>0n > 0, the number rn(x)=∑p,qapq(n)∣xpq∣r_n(x) = \sum_{p,q} a^{(n)}_{pq} |x_{pq}| is finite.

Endowed with the topology defined by the seminorms rnr_n, E is a Fréchet space of countable type (IV, p. 47, exerc. 1, c)); the dual E′E' of E can be identified with the space of double sequences x′=(xpq′)x' = (x'_{pq}) of real numbers such that, for at least one index nn, there exists kn>0k_n > 0 such that ∣xpq′∣≤knapq(n)|x'_{pq}| \leq k_n a^{(n)}_{pq} for every pair (p,q)(p, q), with ⟨x,x′⟩=∑p,qxpqxpq′\langle x, x' \rangle = \sum_{p,q} x_{pq} x'_{pq} (IV, p. 47, exerc. 1, c)).

For every integer p0>0p_0 > 0 and every sequence (mp)(m_p) of integers >0> 0, let J(p0;(mp))J(p_0 ; (m_p)) be the set of pairs of integers p>0,q>0p > 0, q > 0 such that p≥p0p \geq p_0 and q≥mpq \geq m_p; let B\mathscr{B} be the filter base on N×N\mathbf{N} \times \mathbf{N} formed by the sets J(p0;(mp))J(p_0 ; (m_p)) and let F\mathfrak{F} be an ultrafilter finer than the filter base B\mathscr{B}. a) Now prove that for every x′=(xpq′)∈E′x' = (x'_{pq}) \in E', the double sequence (xpq′)(x'_{pq}) has a limit u(x′)u(x') following the ultrafilter F\mathfrak{F}; if VnV_n is the neighbourhood of 0 in E defined by rn(x)≤1r_n(x) \leq 1, one has ∣u(x′)∣≤1|u(x')| \leq 1 for every x′∈Vn∘x' \in V_n^\circ.

b) Let U' be a strong neighbourhood of 0 in E', convex, balanced and weakly closed, and for every n, let αn>0\alpha_n > 0 be such that αnVn∘⊂U′\alpha_n V_n^\circ \subset U'. For every integer p>0p > 0, let mpm_p be an integer such that 2p+1≤αpmp2^{p+1} \leq \alpha_p m_p, and let x′=(xpq′)x' = (x'_{pq}) be the double sequence such that xpq′=0x'_{pq} = 0 for q<mpq < m_p, xpq′=2x'_{pq} = 2 for q≥mpq \geq m_p. Now prove that x′∈U′x' \in U' but that u(x′)=2u(x') = 2; deduce that uu is not strongly continuous in E′E', while being bounded in every bounded part of E′E'. Conclude (IV, p. 58, exerc. 3) that E is not distinguished, and consequently that the strong dual Eb′E'_b is a (DF) space which is not infratonelated. c) Deduce from b) an example of a closed subspace M of a Fréchet space F, such that the strong topology β(F′/M∘,M)\beta(F'/M^\circ, M) is distinct from the quotient topology by M∘M^\circ of the strong topology β(F′,F)\beta(F', F) (embed E in a countable product of Banach spaces).

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.