Bourbaki

Exercise 8, § 3

Topological Vector Spaces, IV, p. 59

Bourbaki marks this one as harder than the rest.

Let E be a Fréchet space, Eb′E'_b its strong dual. We suppose that there exists an everywhere dense sequence (xn′)(x'_n) in Eb′E'_b. Now prove that E is of countable type. (Let (Kn′)(K'_n) be a countable basis of the canonical bornology of Eb′E'_b formed of closed, convex, balanced sets. For every system α\alpha formed of a point xn′x'_n, an arbitrary finite number of rational numbers λk>0\lambda_k > 0 (1≤k≤m)(1 \leq k \leq m) and m indices nkn_k such that xn′∉2∑k=1mλkKnk′=2Hα′x'_n \notin 2 \sum_{k=1}^m \lambda_k K'_{n_k} = 2H'_\alpha, let xα∈Ex_\alpha \in E be such that the hyperplane with equation ⟨xα,y′⟩=1\langle x_\alpha, y' \rangle = 1 strictly separates the two weakly compact sets Hα′H'_\alpha and xn′+Hα′x'_n + H'_\alpha. Now prove that for every x′≠0x' \neq 0 in E′E', there exists a system α\alpha such that ⟨xα,x′⟩≠0\langle x_\alpha, x' \rangle \neq 0. For this, consider a neighbourhood V′V' of 0 in Eb′E'_b such that V′∩(x′+V′)=∅V' \cap (x' + V') = \emptyset, then, for each integer mm, a rational number λm>0\lambda_m > 0 such that λmKm′⊂V′\lambda_m K'_m \subset V'; use the fact that the union U′⊂V′U' \subset V' of the λmKm′\lambda_m K'_m is a neighbourhood of 0 (Exercise 7, c) and IV, p. 58, Exercise 3, b)) and that there exists nn such that xn′∈x′+U′x'_n \in x' + U'.

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.