Bourbaki

Exercise 19, § 1

Topological Vector Spaces, V, p. 64

Bourbaki marks this one as harder than the rest.

Let EE be a complex normed space, of infinite dimension. Suppose that there exists a bijective mapping ω\omega of the set M\mathscr{M} of closed vector subspaces of EE onto itself, having the properties stated in Exercise 18. (a) Now prove that there exists a semilinear mapping uu of EE onto its dual E’E’ (for the automorphism ξ↦ξ‾\xi \mapsto \overline{\xi} of C\mathbf{C}) uniquely determined up to a scalar factor such that u(M)=(ω(M))∘u(M) = (\omega(M))^{\circ} for every M∈MM \in \mathscr{M}. (Proceed as in Exercise 18; using IV, p. 65, Exercise 16, prove that uu is a semilinear mapping relative to the identity automorphism of C\mathbf{C} or to the automorphism ξ↦ξ‾\xi \mapsto \overline{\xi}; finally prove that the first case cannot occur, by observing that ⟨x,u(x)⟩≠0\langle x, u(x) \rangle \neq 0 for x≠0x \neq 0.) (b) If one sets ⟨y∣x⟩=⟨x,u(y)⟩\langle y|x \rangle = \langle x, u(y) \rangle, prove that ⟨x∣y⟩=⟨y∣x⟩‾\langle x|y \rangle = \overline{\langle y|x \rangle} and that ⟨x∣x⟩\langle x|x \rangle has a constant sign in the set of the x≠0x \neq 0 (same method as in Exercise 18). (c) Finally prove that the topology defined by the norm ⟨x∣x⟩1/2\langle x|x \rangle^{1/2} is finer than the initial topology T0\mathscr{T}_0 on EE, and that these two topologies are identical when EE is complete for T0\mathscr{T}_0; in this last case, ω(M)\omega(M) is the orthogonal supplement of MM in the Hilbert space EE.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.