Bourbaki

Exercise 12, § 1

Functions of a Real Variable, II, p. 30

Bourbaki marks this one as harder than the rest.

One says that a sequence (xn)(x_n) of real numbers belonging to the interval (0,1)(0, 1) is equally distributed in this interval if, for every pair of numbers α,β\alpha, \beta such that 0≤α≤β≤10 \leq \alpha \leq \beta \leq 1 one has, denoting by vn(α,β)v_n(\alpha, \beta) the number of indices ii such that 1≤i≤n1 \leq i \leq n and α≤xi≤β\alpha \leq x_i \leq \beta

lim⁡n→∞vn(α,β)n=β−α. \lim_{n \to \infty} \frac{v_n(\alpha, \beta)}{n} = \beta - \alpha.
Prove that, if the sequence (xn)(x_n) is equally distributed, and if ff is a regulated function in (0,1)(0, 1), one has
lim⁡n→∞1n∑i=1nf(xi)=∫01f(t)dt \lim_{n \to \infty} \frac{1}{n} \sum_{i=1}^n f(x_i) = \int_0^1 f(t) dt
(reduce to the case where ff is a step function). Converse. Prove that, in order that the sequence (xn)(x_n) be equally distributed, it is sufficient that relation (2) hold for every numerical function ff belonging to an everywhere dense set in the space of continuous numerical functions in [0,1][0, 1], endowed with the topology of uniform convergence.

Solution

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Machine translation of the English, by gpt-5-6. Not checked by a person.