Bourbaki

Exercise 14, § 1

Functions of a Real Variable, II, p. 31

Let f\mathbf{f} be a vector-valued primitive function of a regulated function f′\mathbf{f}' in [a,b][a, b], and such that f(a)=f(b)=0\mathbf{f}(a) = \mathbf{f}(b) = 0. Now prove that if MM is the supremum of ∥f′(x)∥\| \mathbf{f}'(x) \| in the set of points of [a,b][a, b] where f′\mathbf{f}' is continuous, one has

∥∫abf(t) dt∥≤M(b−a)24. \left\| \int_a^b \mathbf{f}(t) \, dt \right\| \leq M \frac{(b - a)^2}{4}.

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.