Exercise 13, § 1
Integration, II
Bourbaki marks this one as harder than the rest.
(a) Let E be a completely reticulated space. If is an arbitrary element of E, now prove that the set of such that there exists an integer for which , is a completely reticulated and coreticulated subspace (exerc. 3) of E. For every , denote by the greatest lower bound of the scalars such that ; now prove that is a norm on (use the fact that E is Archimedean (exerc. 5)), that, endowed with this norm, is complete, and that one has .
(b) Let be the set of components of on the bands of the space ; now prove that is the set of elements of such that and (use the Riesz theorem). Now prove that is closed in the normed space and that, for the order relation induced by that of , is a complete Boolean lattice (Ens., chap. III, 2nd ed., § 1, exerc. 11 and 17; it is enough to prove that, if is a family of elements of , sup belongs to ).
(c) Let be an arbitrary element of ; for every , let be the component of on the band of generated by . Now prove that if , one has ; for , one has , and for , one has . Now prove that if is such that , the component of on the band generated by is (notice that the bands generated by and by are identical, and that the component of on this band is equal to that of ; deduce that the component of on this same band is ). Prove similarly that if is such that , the component of on the band generated by is .
) We know (Top. gén., Chap. II, 3\textsuperscript{e} ed., § 4, exerc. 12) that there exists an isomorphism of ordered structure of the Boolean lattice onto the Boolean lattice formed by the characteristic functions of the sets which are both open and closed in a totally disconnected compact space S. Show that the relation implies that the function is zero in S (use the decomposition lemma); deduce from this remark and from that the mapping extends to an isomorphism of the normed space onto the normed space of finite continuous numerical functions in S, such that . (With the aid of ), show that for every and every , there exists a growing sequence of real numbers such that and that
) For S to be finite, it is necessary and sufficient that be of finite dimension; deduce from this (with the aid of exerc. 12) that every completely reticulated space of finite dimension is isomorphic to a product space (cf. § 2, exerc. 7).
) Show that S is an extremely disconnected space (Top. gén., Chap. I, 3\textsuperscript{e} ed., § 11, exerc. 21) (use the fact that is a complete lattice). A compact extremely disconnected space is called a stonian space. Show that if X is a stonian space, for every numerical function lower semi-continuous in X, the upper semi-continuous regularization g of (Top. gén., Chap. IV, 3\textsuperscript{e} ed., § 6, No. 2) is continuous (for every , show that cannot be adherent to the (open) set of the such that , by observing that at a point adherent to this set, one has ). Deduce that is then a completely reticulated space. Show that when the stonian space X is infinite, the supremum in of a bounded above set is not necessarily equal to its upper envelope (consider an open non-closed set in X); nevertheless these two functions are equal in the complement of a meagre set (consider the set of points where their difference is ).
) Let X be a stonian space; show that if is a bounded numerical function, defined in the complement of a rare subset M of X, and continuous in , then extends by continuity to all of X (use the fact that is completely reticulated). Deduce that the set of numerical functions finite or not, continuous in X, and such that and are rare in X is a completely reticulated vector space.
) Show that the band generated by in E is isomorphic (as an ordered space) to an isolated subspace (exerc. 4) of (consider an element of as the supremum of the elements ).
Solution
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